You call this a mathematical riddle...?
This is a mathematical riddle.
Let (an) be a sequence defined as follows: a1 is a positive integer and an = int((3/2) × a(n-1)) + 1, where int = rounding down to the next smallest integer.
Is it possible to choose a1 such that a100001 is odd and an is even for n < 100001 ?
Turns into a mathematical thread
To get rid of 0.5x
It's actually optional:
10 + 0.5x = x
10 = 0.5x
10/(1/2) = x
10 * 2 = x
x = 20
@Jabuuty671
Last edited by 666HiddenMaster666; 04-01-2011 at 05:05 PM.
Niggas are scared of my riddle.
@Ethereal
What level of math is it?