2. Originally Posted by somewhatpro
Alright, since you boys are done playing let me show you the real way we do things around here.

Suppose we have a list here for all the times the 7 Appears in the last decimal place (7, X7, XX7, example : 147) Lets call the list U.

U = {7, 17, 27, 37,..., 877}
The equation for any n is Un = 7 + 10n. so:

877 = 7 + 10n
870 = 10n
n = 87 so the number 7 appears 87 times in the last decimal place.

1 - Thus, Utotal = 87
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Now , suppose we have another list for all the times the number 7 Appears in the second decimal place (7X, X7X, example : 70, 570) lets call this list U'
U' = {70, 170, 270, 370, ... , 870}
The equation for any n for this list would be : U'n = 70 + 100n
so:
870 = 70 + 100n
800 = 100n
n = 8 so the number 7 appears 9 times in the second decimal place.

2 - Thus, U'total = 9 ( the reason it is 9 is because we didn't add the first number (n = 0) )
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Now we need another list to find out how many times the 7 appears in the second decimal place (7X, X7Y, example : 76)
Lets call this list Z.
Zn = {70, 71, 72,..., 79} =======> it appears 10 times for every 100 in the U' list

3 - So..., Ztotal = 9 * U'total = 90

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Now lets see how many times the number 7 Appears in the first decimal place.. well this is easy, 7XX
the only number that has 7 in the first place in the range 1 - 877 is 700 so. it appears 1 time only.
But how many times does the number 7 appear from 700 to 799 ?? well thats also easy, it appears 100 times !

SO, the total times the number 7 appears is :

Utotal + Ztotal + 100*1 = 87 + 90 + 99 = 276

The number 7 appears 276 times from 1 to 877.

Okay now @iCudi , you better have me rewarded because i wasted valuable time figuring this out... so you better 10/10 me. bich.
wat

3. Originally Posted by somewhatpro

YESS! bitch, see that shit?.. @Predator i got a cookie son.

4. Originally Posted by Predator