1st one, its not about physics i guess, its about pythagoras math theory or something like that
basically you squared 23 and 4, which is 529 and 16
add it up and square root it, but idk why i got 23.3452...
I Need Help Please. (Please Tell Me How You Found The Answer, Because I Have Other Questions Similar To This)
1.) Bill Walked 23 Miles West Then Walked 4 Miles North, Determine The Following.
A. The Distance Bill Walked __________________________
B. Bill's Displacement, R/0
2.) A 24 KG Crate Is Pushed By A 624 Newton Force. Determine The Following.
A.)Weight Of Box.
B.)Force Of Friction If U (MU) Is 0.242
C.)The Net Force
D.)The Acceleration (If Any)
3.) A 32 KG Crate Is On An Inclined ( Ø = 16 Degree) Which Has A U =0.33 Determine The Folowing
A.Weight Of Crate
B.Fu
C.Fperpendicular (I Can't Draw The Upside Down T)
D. Acceleration
Please Write Down How You Got The Answers If You Do Answer Them Thx
Keep in mind The A,B,C,D are the things you need to solve, this is not multiple choice -_-
Last edited by cuckold cancer 8=D; 12-09-2014 at 10:05 PM.
1st one, its not about physics i guess, its about pythagoras math theory or something like that
basically you squared 23 and 4, which is 529 and 16
add it up and square root it, but idk why i got 23.3452...
[MPGH]cuckold cancer 8=D (12-09-2014)
1.)
A. Distance = 23 Miles West + 4 Miles North.
``It is asking for the total distance that he walked.
B. To solve this question, you have to use Pythagorean theorem because he walked 23 west and 4 miles north.
You drew a line that goes west and put 23 there.
Then draw a line that goes up connected to the last west line you drew.
It will form a
___|
so you have to solve the missing spot which is the " / " in order to form a triangle.
You have to use the a^2+b^2=c^2
``It is asking for the progress that he walked.
The question mark is the displacement. The direction does not matter but sometimes you have to state them when your teacher asks you to do so.
Sorry my english is not good.
Last edited by Source Unknown; 12-09-2014 at 10:30 PM.
=========================Omega good job!========================
[MPGH]cuckold cancer 8=D (12-09-2014)
If you are looking for the total distance, trust me it is just a plus.
For the second one.
Variables:
m = 24kg
fa = 624N
u= .242
mg = ???
fnet = ???
The weight of the box is = Mass x Gravity. Simply because it is a downward force.
The force appiled is 624 Newton
The friction is = u x mg
Fnet is = Fa - ff. It is minus because the force are in opposite directions.
Acceleration = probably none since it is a flat surface.
Last edited by Source Unknown; 12-09-2014 at 10:48 PM.
=========================Omega good job!========================
[MPGH]cuckold cancer 8=D (12-09-2014)
2) A)F = ma = (24 kg)(9.8 m/s/s) = 235.2 N
B) fk = µkmg cos θ
=(0.242)(24kg)(9.8m/s/s)Cos 90
=(im too lazy to find my calculator)
C)?Don't know
D)Sum of forces (vertical forces cancel as evidenced by lack of acceleration in the vertical dimension)
Fnet = T + Ff
Fnet = (624) + (-(answer of the friction)) = ?? N
i guess thats it . but I will edit thought if i get the other answers . currently having a headache
"Holding anger is a poison. It eats you from inside. We think that hating is a weapon that attacks the person who harmed us. But hatred is a curved blade. And the harms we do, we do to ourselves."-Mitch Albom
[MPGH]cuckold cancer 8=D (12-09-2014)
Awesome, perfect. Give me a few minutes to solve the third one.
=========================Omega good job!========================