This is 5th grade bs.. lel, anyways
The Pythagorean theorem states that the square of the hypotenuse (the side opposite to the right angle) is equal to the sum of the squares of the other two sides
If you know please do this question
<---------- Is That Right?
This is 5th grade bs.. lel, anyways
The Pythagorean theorem states that the square of the hypotenuse (the side opposite to the right angle) is equal to the sum of the squares of the other two sides
Zuhrain (01-22-2015)
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SMD SMD SMD SMD SMD SMDSMMSMDFASDFAS
(a^2)+(b^2)=(c^2)
(x^2)+(10^2)=((x+6)^2)
(x^2)+100=((x^2)+12x+36)
Move your quadratic or degree 2 polynomial to which ever side and set it equal to zero. Solve for your x values.
Typing it on the computer is rather confusing.
Edit: You should get +/- 16/3
- - - Updated - - -
"Question has nothing to do with the theorem, but mostly sin cosine and tangent"
You are not given an angle. Your sides have "x" as the variable.
If you do not have an angle, that will be a y
For example:
You will get siny=x/x+6
You can't solve that unless you introduce another equation for substitution or elimination.
Last edited by Hugo Boss; 01-22-2015 at 07:29 PM.
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[DIN]Royce[DU] (01-22-2015)
The only correct answer is 16/3. There is no second solution since:
(x+6)^2=x^2+10^2
x^2+12x+36=x^2+100 |-x^2
12x+36=100 |-36 |:12
x=16/3=5.3333333333333333333333333333333333333333333333 33333333333333333333333333333333333333333333333333 3333333333333333333
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Youtro (01-24-2015)