# Thread: Anyone here know Pythagorean theorem?

1. ## Anyone here know Pythagorean theorem?

If you know please do this question

2. This is 5th grade bs.. lel, anyways
The Pythagorean theorem states that the square of the hypotenuse (the side opposite to the right angle) is equal to the sum of the squares of the other two sides

3. ## The Following User Says Thank You to HeroicXPharaoh For This Useful Post:

Zuhrain (01-22-2015)

4. Question has nothing to do with the theorem, but mostly sin cosine and tangent

Originally Posted by HeroicXPharaoh
This is 5th grade bs.. lel, anyways
The Pythagorean theorem states that the square of the hypotenuse (the side opposite to the right angle) is equal to the sum of the squares of the other two sides
damn if only he asked for the definition

5. How old are you?

6. (a^2)+(b^2)=(c^2)
(x^2)+(10^2)=((x+6)^2)
(x^2)+100=((x^2)+12x+36)

Move your quadratic or degree 2 polynomial to which ever side and set it equal to zero. Solve for your x values.
Typing it on the computer is rather confusing.

Edit: You should get +/- 16/3

- - - Updated - - -

Originally Posted by Royce
Question has nothing to do with the theorem, but mostly sin cosine and tangent

damn if only he asked for the definition
"Question has nothing to do with the theorem, but mostly sin cosine and tangent"
You are not given an angle. Your sides have "x" as the variable.
If you do not have an angle, that will be a y
For example:
You will get siny=x/x+6
You can't solve that unless you introduce another equation for substitution or elimination.

7. ## The Following User Says Thank You to Hugo Boss For This Useful Post:

[DIN]Royce[DU] (01-22-2015)

8. The only correct answer is 16/3. There is no second solution since:
(x+6)^2=x^2+10^2
x^2+12x+36=x^2+100 |-x^2
12x+36=100 |-36 |:12
x=16/3=5.3333333333333333333333333333333333333333333333 33333333333333333333333333333333333333333333333333 3333333333333333333

9. I forgot.

10. Originally Posted by Hugo Boss
(a^2)+(b^2)=(c^2)
(x^2)+(10^2)=((x+6)^2)
(x^2)+100=((x^2)+12x+36)

Move your quadratic or degree 2 polynomial to which ever side and set it equal to zero. Solve for your x values.
Typing it on the computer is rather confusing.

Edit: You should get +/- 16/3

- - - Updated - - -

"Question has nothing to do with the theorem, but mostly sin cosine and tangent"
You are not given an angle. Your sides have "x" as the variable.
If you do not have an angle, that will be a y
For example:
You will get siny=x/x+6
You can't solve that unless you introduce another equation for substitution or elimination.
I seen 90 degress and dun goofed

11. Shoutout to all my racist 12 year olds holding down the fort.

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Youtro (01-24-2015)