Thread: Math problem...

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  1. #1
    Capevaldo's Avatar
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    Math problem...

    Can someone help me ?

    Determine the equation of bisector straight r on AB segment.
    Information:
    A(1, 4)
    B(3, 2)

    Thanks @Jigsaw for translating

  2. #2
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    And sorry for my translation.
    DEHUMANIZE YOURSELF
    AND FACE TO BLOODSHED

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    Ravallo's Avatar
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    Could you tell me the name of the Chapter? Or the name of this particular Subject? I don't know any mathematical language, in English.

    I believe @Alen is pretty good at Maths


     

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  4. #4
    Dr.Dental's Avatar
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    @Capevaldo
    @Ravallo: This question is quite an advanced linear graph question. It's about a year 9-11 question. It involves calculating midpoints, finding the normal/gradient of a graph, finding equations by using formulas etc.
    First of all, find the mid point.
    (2,3)

    Second, find the the gradient of the 2 points using the formula: y1-y2/x1-x2= 4-2/1-3=2/-2=-1
    Therefore m= -1.
    The bisector must be the normal of the gradient as it is perpendicular.
    Normal= -1/m
    Therefore the gradient of your bisector is -1/(-1) which is 1.

    Use the formula
    y2-y1=m(x2-x1)
    sub in the midpoint and gradient of the bisector
    y-3=1(x-2)
    y=x+1

    Sorry if I'm wrong, I was in a rush.




    If in assistance of any math problems, I can try to assist you in the future.
    Last edited by Dr.Dental; 05-12-2011 at 05:05 AM.

  5. The Following User Says Thank You to Dr.Dental For This Useful Post:

    Capevaldo (05-12-2011)

  6. #5
    Capevaldo's Avatar
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    I think you're right, @Foxy.

    My math book has answers for exercises... the answer for this exercise is
    x - y + 1 = 0

    And your answer is: y = x + 1 ~~> x - y + 1 = 0
    *-*
    Last edited by Capevaldo; 05-12-2011 at 02:05 PM.