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  1. #1
    Braco22's Avatar
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    Large Char Array!

    I need help creating a long char array. Or is there a much simpler way to do this? I dont want to type it out to 30000. Is there a much shorter way to do this?

    char *num[] = { "1", "2", .., "29000", "30000" };

  2. #2
    matypatty's Avatar
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    Dude come on this is easy... I'll give you something to work with...
    Code:
    int yourgayarray[];
    for( int i =0; i < 3000; i++ ) 
    {
    yourgayarray[i] = i;
    }
    use ints its better and easier
    Last edited by matypatty; 08-30-2011 at 11:15 PM.

  3. #3
    flameswor10's Avatar
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    Use a For loop and Sprintf function
    No I do not make game hacks anymore, please stop asking.


    Been MPGH Minion: 6 July 2011 - 1 August 2012

  4. #4
    Departure's Avatar
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    Quote Originally Posted by matypatty View Post
    Dude come on this is easy... I'll give you something to work with...
    Code:
    int yourgayarray[];
    for( int i =0; i < 3000; i++ ) 
    {
    yourgayarray[i] = i;
    }
    use ints its better and easier
    He asked for a Char Array, Not an array of integers.......

    same principle apply's

    for i:= 0 to 3000 do
    CharArray[i]:= IntToStr(i); <--- convert Integer to a String..

  5. #5
    flameswor10's Avatar
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    Quote Originally Posted by Departure View Post
    He asked for a Char Array, Not an array of integers.......

    same principle apply's

    for i:= 0 to 3000 do
    CharArray[i]:= IntToStr(i); <--- convert Integer to a String..
    Sprintf should do the job.
    No I do not make game hacks anymore, please stop asking.


    Been MPGH Minion: 6 July 2011 - 1 August 2012

  6. #6
    Braco22's Avatar
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    Quote Originally Posted by Departure View Post
    He asked for a Char Array, Not an array of integers.......

    same principle apply's

    for i:= 0 to 3000 do
    CharArray[i]:= IntToStr(i); <--- convert Integer to a String..
    where would i place this. i can't put it as global though.

    i am doing this

    Code:
    	for(int i = 0;  i < 30000; i++)
    	{
    		largeArray[i] = (char *)i;
    	}
    but my menu crashes when i want to turn on the hack to like 500

    another method i tried but crashes

    Code:
    	char buffer [ FILENAME_MAX ];
        for(int i = 0;  i < 30000; i++)
    	{
    		sprintf(buffer, "%d", i);
    		largeArray[i] = buffer;
    	}
    
    	return 0;
    Last edited by Braco22; 08-31-2011 at 08:03 AM.

  7. #7
    _Fk127_'s Avatar
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    Quote Originally Posted by Braco22 View Post
    where would i place this. i can't put it as global though.

    i am doing this

    Code:
    	for(int i = 0;  i < 30000; i++)
    	{
    		largeArray[i] = (char *)i;
    	}
    but my menu crashes when i want to turn on the hack to like 500

    another method i tried but crashes

    Code:
    	char buffer [ FILENAME_MAX ];
        for(int i = 0;  i < 30000; i++)
    	{
    		sprintf(buffer, "%d", i);
    		largeArray[i] = buffer;
    	}
    
    	return 0;
    In this loop, i is an of an int data type. You are referencing it in your sprintf method call as a double (%d)
    Code:
     for(int i = 0;  i < 30000; i++)
    	{
    		sprintf(buffer, "%i", i);
    		largeArray[i] = buffer;
    	}



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  8. #8
    ISmokeWeedAmICoolNow's Avatar
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    Code:
    char* None[30000];
    for (int Of = 0; Of < 30000; ++Of)
    {
    	char* YouKnowCPP = new char[15];
    	_itoa(Of, YouKnowCPP, 10);
    	None[Of] = YouKnowCPP;
    }
    Last edited by ISmokeWeedAmICoolNow; 08-31-2011 at 03:13 PM.

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  10. #9
    freedompeace's Avatar
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    Quote Originally Posted by Braco22 View Post
    I need help creating a long char array. Or is there a much simpler way to do this? I dont want to type it out to 30000. Is there a much shorter way to do this?

    char *num[] = { "1", "2", .., "29000", "30000" };
    Code:
    int len = 30000;
    char* num[] = new char*[len];
    for (int i = 0; i < len; i++)
      num[i] = iota(i);
    Present!

    Quote Originally Posted by matypatty View Post
    Dude come on this is easy... I'll give you something to work with...
    Code:
    int yourgayarray[];
    for( int i =0; i < 3000; i++ ) 
    {
    yourgayarray[i] = i;
    }
    use ints its better and easier
    Unfortunately, you can't just assume that without knowing what the purpose of the array is.
    Last edited by freedompeace; 09-02-2011 at 03:08 AM.

  11. #10
    matypatty's Avatar
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    Why do a char when it's easier to do an int but w/e

  12. #11
    topblast's Avatar
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    Quote Originally Posted by Braco22 View Post
    where would i place this. i can't put it as global though.

    i am doing this

    Code:
    	for(int i = 0;  i < 30000; i++)
    	{
    		largeArray[i] = (char *)i;
    	}
    but my menu crashes when i want to turn on the hack to like 500

    another method i tried but crashes

    Code:
    	char buffer [ FILENAME_MAX ];
        for(int i = 0;  i < 30000; i++)
    	{
    		sprintf(buffer, "%d", i);
    		largeArray[i] = buffer;
    	}
    
    	return 0;
    LOL

    Code:
    	char* largeArray[30000];
            for(int i = 0;  i < 30000; i++)
    	{
                    char buffer [ 0x10 ];
    		sprintf_s(buffer, "%d", i);
    		largeArray[i] = buffer;
    	}
    
    	return 0;
    I just like programming, that is all.

    Current Stuff:

    • GPU Programmer (Cuda)
    • Client/Server (Cloud Server)
    • Mobile App Development

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