Way to use us for the wrong section...
And we'd probably just give you the wrong answers.
A 700 g weight is held on a steel cable and spun in a vertical circle. If the cable can withstand a tension of 4100 N, at what velocity will the cable break. (Hint the tension is not the same throughout the period of rotation?
EDIT: I'm really sorry if this is the wrong section! Just send me a warning and I promise I'll watch myself next time!
Way to use us for the wrong section...
And we'd probably just give you the wrong answers.
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ZigZak (03-19-2013)
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ZigZak (03-19-2013)
@iverson954360
I found this question somewhere else just now, but the thing is, you need radius to calculate this... And where I found the answer it says to assume the radius is 1m.
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You need to give us the radius or the tension in order for me to solve this equation aff
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Originally Posted by KingDot
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Ivy to the rescue
Well then little kid /aff You're lucky I don't feel like doing my political cartoon aff
According to the centripetal force formula
Fc (subscript c) = mv^2 / 2
Fnet (subscript net) = ma, which is equal to Ft (tension subscript) - Fg (gravity subscript).
This will give you 4100 - (0.700)(9.81) = mv^2 / r = (0.700)v^2 (We use 4100 because tension is greater bottom of the rotation and less on the top)(We will use the 4100 on the top because the rotation is vertical. The top part is according to the gravity, and the bottom is going against it)
This will get you 4093.133 = 0.7v^2
4093.11 / 0.7 = 5847.33
Squareroot that and you get 76.47 rounded to the tenth.
Now in your original question the lowest significant digit is 1, so it would become 8*10^1
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Originally Posted by KingDot
ALL THIS KNOWLEDGEEEEEEEEEE
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ZigZak (03-20-2013)
We need extra information, we can't work it out from 1 set of results, this case (N), we need radius.
Usually looking at these equations and their constituents will usually help you figure out what to use to solve the problem.