time delay to the moon

[lalakijilp]

in my tutorial was a program to calculate the time delay to the mars.

the output is:

Time delay when talking to Mars: 182.796 seconds. This is 3.04659 minutes.

now i wanted to make to look like this:

Time delay when talking to Mars is 3 minutes and ?? seconds.
this is what i did:

but it didn't work out so how can i make it work?

#include <iostream>
using namespace std;

int main ()
{
double distance, lightspeed, delay, delay_in_min, seconds;
int delay_in_min_2;

/* i added int delay_in_min_2; to calculate the seconds left after the whole minutes (minutes-minutes rounded)*60 */

distance = 34000000.0;
lightspeed = 186000;

delay = distance/lightspeed;

cout << "Time delay when talking to mars: " << delay << " seconds." << endl;

delay_in_min= delay/60.0;

cout << "This is " << delay_in_min << " minutes." <<endl;

seconds = (delay_in_min-delay_in_min_2)*60;

// [Warning ] converting to int from double. how to do it else?

delay_in_min_2= ((distance/lightspeed)/60);

cout << "Time delay when talking to mars: " << delay_in_min_2 <<" minutes and " << seconds <<endl;


system ("pause");

return 0;

}

edit: oops wrong title i mean mars. xD

[zeco]

in my tutorial was a program to calculate the time delay to the mars.

the output is:

Time delay when talking to Mars: 182.796 seconds. This is 3.04659 minutes.

now i wanted to make to look like this:

Time delay when talking to Mars is 3 minutes and ?? seconds.
this is what i did:

but it didn't work out so how can i make it work?



edit: oops wrong title i mean mars. xD

Well one thing is when you first used delay_in_min_2, it wasn't given a value yet

[lalakijilp]

Well one thing is when you first used delay_in_min_2, it wasn't given a value yet

i changed it but it wont work yet

[rwkeith]

Is this C#? Cause I tried working with it and I have a few undefined functions.

[lalakijilp]

no, it is C++

this was the error.

[Warning ] converting to int from double.

i put it in the code too. hwo to do it otherwise

[rwkeith]

Ah, I see almost complete with a solution. By the way, did you get an error about your delay_in_min_2? I had to fix it because my compiler said unknown identifier.

//myfirst.cpp--displays a msg

#include <iostream>

using namespace std;

int main ()
{
double distance;
double lightspeed;
double delay;
double DelayInMin;
double seconds;
int DelayInMin2;

// I smoothed things into my own style a little =)

distance = 34000000.0;
lightspeed = 186000;

delay = distance/lightspeed;

cout << "Time delay when talking to mars: " << delay << " seconds." << endl;

DelayInMin = delay/60.0;

cout << "This is " << (int)DelayInMin << " minutes." <<endl;
DelayInMin2 = ((distance/lightspeed)/60);//You must declare the variable before using it =), or at least in my case =S
seconds = (DelayInMin-DelayInMin2)*60;

// [Warning ] converting to int from double. how to do it else?



cout << "Time delay when talking to mars: " << (int)DelayInMin2 << " minutes and " << (int)seconds << " seconds.";

cin.get();

return 0;

Ok, simply when you want your answer to be a different type place the type you want it to be in parenthensies. Ex.:

//This is an example =P

double test = 10.56567
cout << "I will reveal to you an integer: " << (int)test;

The result of this would be 10...

[lalakijilp]

so you can change a double to an int by putting (int) before it?

[rwkeith]

Yes and ignore the (int) I put in this line of code, it isn't required

[why06]

so you can change a double to an int by putting (int) before it?

Yes. it's called casting a variable. It forces a variable to another type. In Java compilers won't even allow a double value to be entered into a int without casting, but C++ allows a lot more freedom in this regard with it's automatic type conversion. The problem with automatic type conversion is that it can lead to ambiguity too.


Also here is how I would have coded your delay calculator:

#include <iostream>
using namespace std;

int main()
{
    double distance, delay;
    double SoL = 186000; //miles per second
    
    cout << "LightSpeed Delay Calculator\n" ;
    cout << "Enter distance in miles: \n";
    cin >> distance;
    int seconds = (int)(distance/SoL);
    cout << "The time delay for a distance of " << distance << " miles is " << seconds/60 << " minutes and " << seconds%60 << " second(s).";
    
    system("pause");
    return 0;
}

I used and operator called mod "%" to only return the remainder when I divided the seconds by 60. right now I'm trying to work on a program that will automatically give minutes, hours, days, seconds, etc. depending on the amount of delay. The trouble is keeping all the "/60" and "%60" in my head. I think I will create a funtion to handle this that way only have to call that function and can keep the math out of the cout statements.

[why06]

Well it took long enough, and got kinda confusing at times, and I could have gone about it a different way, but here is my completed version that automatically calculates years, days, hours, minutes, and seconds.

Unfortunately it breaks if you inter a value bigger then an integer can hold. It also breaks if you enter something that isn't a number. But hey this is all the effort I'm gonna put into it since I will probably never use it :P

#include <iostream>
using namespace std;

void time(double seconds);

int main()
{
    double distance, delay;
    double SoL = 186000; //miles per second
    
    cout << "LightSpeed Delay Calculator\n" ;
    cout << "Enter distance in miles: \n";
    cin >> distance;
    
    delay = distance/SoL;
    
    cout <<"The calculated time delay is: ";
    time(delay);
    cout<<endl ;
    
    system("pause");
    return 0;
}
    
// a function that will take parameters in seconds and convert to cyclical time.    

void time(double seconds)
{    
    int minute = 60;
    int hour = 3600;
    int day = 3600*24;
    int year = 3600*24*365;
    
    int second = (int)seconds;
    
    int perfectseconds = second%minute;
    int perfectminutes = ((second/minute)%60);
    int perfecthours =  ((second/hour)%24);
    int perfectdays =  ((second/day)%365);
    int perfectyears = (second/year);

     if(seconds < year)
     {
                if(seconds < day)
                {
                           if(seconds < hour)
                           {
                                      if(seconds < minute)
                                      {
                                                 cout << (int)seconds << " seconds";
                                      }
                                      else cout << perfectminutes << "minutes and " << perfectseconds  << " seconds";
                           }
                           else cout << perfecthours << "hours " << perfectminutes << " minutes and " << perfectseconds << "seconds";
                }
                else cout << perfectdays << "days " << perfecthours << " hours " << perfectminutes << " minutes " << perfectseconds << "seconds";
     }
     else cout << perfectyears << "years " << perfectdays << " days" << perfecthours << " hours " << perfectminutes << " minutes " << perfectseconds << "seconds";
}

you can compile this code and it should run.