Fags.

[Gill Bates]

In case there are some smart people left on MPGH,I have a question that'll make you work for a little while.

How many '2's appear from 0-332?

It should take you less than 12 minutes.
Google it and you're a ******.

[Aborted]

69,420,666
​...

[Gill Bates]

69,420,666
​...

Close

[-Lame]

Your mom take less than 12 minutes.

[Gill Bates]

Your mom take less than 12 minutes.

Not with your small dick.

[TheFrikinAsian]

0-332?

2 or 48, depending on how you ask the question. :P 48 if you meant all whole numbers ranging from 0 to 332.

- Edit -

Me being a Cocksucker and all, I dang fucked up. Reposting below.

[Reav3R]

Only one unless they teach you how to count differently where you come from.

[Predator]

The numbers I came up with:
2 (1)
12 (1)
22 (1)
32 (1)
42 (1)
52 (1)
62 (1)
72 (1)
82 (1)
92 (1)
102 (1)
112 (1)
122 (2)
132 (1)
142 (1)
152 (1)
162 (1)
172 (1)
182 (1)
192 (1)
202 (2)
212 (2)
222 (3)
232 (2)
242 (2)
252 (2)
262 (2)
272 (2)
282 (2)
292 (2)
302 (1)
312 (1)
322 (2)
332 (1)

Well I fucked up and I'm too tired to fix it. I posted a fix below...

So basically you need to add in the values:
20-29
120-129
200-299
320-329

After that you calculate the number of "2's" found in the numbers. Keep in mind some numbers will contain 3 2's such as 222 and a good amount will have 2 "2's" such as 322 or 122 or 22

Feel free to calculate it yourself, I'm pretty sure I set it all up for you

Oh yeah.. Let's assume its all WHOLE NUMBERS. So decimals won't count.

[Mr.Seyeko]

The numbers I came up with:
2 (1)
12 (1)
22 (1)
32 (1)
42 (1)
52 (1)
62 (1)
72 (1)
82 (1)
92 (1)
102 (1)
112 (1)
122 (2)
132 (1)
142 (1)
152 (1)
162 (1)
172 (1)
182 (1)
192 (1)
202 (2)
212 (2)
222 (3)
232 (2)
242 (2)
252 (2)
262 (2)
272 (2)
282 (2)
292 (2)
302 (1)
312 (1)
322 (2)
332 (1)

Every digit that contains "2" was added together, thus adding up to: 47

would't all the 200's be like 201 202 203 204 205 206 etc etc... all count as well?
or am i just a dumb ass and confused af?

[Predator]

would't all the 200's be like 201 202 203 204 205 206 etc etc... all count as well?
or am i just a dumb ass and confused af?

Yeah I literally was just about to go to sleep when I realized that...

So basically you need to add in the values:
20-29
120-129
200-299
320-329

[RedSpot]

The numbers I came up with:
2 (1)
12 (1)
22 (1)
32 (1)
42 (1)
52 (1)
62 (1)
72 (1)
82 (1)
92 (1)
102 (1)
112 (1)
122 (2)
132 (1)
142 (1)
152 (1)
162 (1)
172 (1)
182 (1)
192 (1)
202 (2)
212 (2)
222 (3)
232 (2)
242 (2)
252 (2)
262 (2)
272 (2)
282 (2)
292 (2)
302 (1)
312 (1)
322 (2)
332 (1)

Well I fucked up and I'm too tired to fix it. I posted a fix below...

So basically you need to add in the values:
20-29
120-129
200-299
320-329

After that you calculate the number of "2's" found in the numbers. Keep in mind some numbers will contain 3 2's such as 222 and a good amount will have 2 "2's" such as 322 or 122 or 22

Feel free to calculate it yourself, I'm pretty sure I set it all up for you

what about 20?
and 20-29

[Predator]

what about 20?
and 20-29

Read what you just quoted...

[Predator]

New Updated Answer: Updated my answer, its the first post on page 2

Did it in a hurry so I can get some damn sleep...

2 (1)
12 (1)
(11)
32 (1)
42 (1)
52 (1)
62 (1)
72 (1)
82 (1)
92 (1)
102 (1)
112 (1)
(11)
132 (1)
142 (1)
152 (1)
162 (1)
172 (1)
182 (1)
192 (1)
200 - 210 (11)
(11)
(12)
11
66
302 (1)
312 (1)
11
332 (1)

Pretty much followed what I said on my above post. If I got it wrong, then it must be my work. But who cares... its 12:00 and its time for me to sleep

[RedSpot]

Read what you just quoted...

I refreshed then baam i see your post, apology master.

[TheFrikinAsian]

2, 12, 22, 32, 42, 52, 62, 72, 82, 92...

Total: 11

200 to 299, there are 100 '2's plus the various '2's above

Total: 122

300 to 332, there is 5 '2's

Total: 127