Thread: If you divide by zero, is it undefined or infinity.

1. X = Impossible
So basicly it's not possible .. not a big deal..

Btw .. for example if you say 5 x 5 = 25
Then 25 / 5 = 5
But you can't do 5 x 0 = 0 , 0 / 0 or 0 / 5

So it's just impossible , stop making another law..

2. Undefined

3. The distinction between undefined and infinity is more clear when you move into calculus and start touching on limits and derivatives. You'll learn that while 0 is undefined, while you approach 0 you will head into infinity.

4. Confusing math

5. The Following User Says Thank You to J Miliam For This Useful Post:

♪~ ᕕ(ᐛ)ᕗ (04-14-2011)

6. You will never find out

7. Originally Posted by Jetamay
State your nerdy arguments here. I say it's niether, it's more like breaking the fundemental laws of algebra

1/0 = x
so in theory,
1 = 0x
1 = 0
Not possible. So division of zero is not undefined nor is it infinity because it breaks the laws of mathematics :O
Igir is right.

Multiplying 0 is not a valid algebraic property, your theorem is invalid.

FAILED.

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edit

Fuck I just realized how stupid it sounds. What Igir said is just dumb, but I think he knows what I know. Lemme try to explain it since I don't know the name of it. Basically, moving 1/0 = x to 1 = 0x is IMPOSSIBLE. You can never plug anything in for x that will equal one. You can't divide by zero in the first place, so moving it over is STILL INVALID.

8. Originally Posted by arunforce

Igir is right.

Multiplying 0 is not a valid algebraic property, your theorem is invalid.

FAILED.

-------------

edit

Fuck I just realized how stupid it sounds. What Igir said is just dumb, but I think he knows what I know. Lemme try to explain it since I don't know the name of it. Basically, moving 1/0 = x to 1 = 0x is IMPOSSIBLE. You can never plug anything in for x that will equal one. You can't divide by zero in the first place, so moving it over is STILL INVALID.
Fuck you , you just made it more worse..

9. It's 0. /fp

0 of anything is 0. 0 goes into something 0 times.... It ain't difficult...

10. Originally Posted by arunforce

Igir is right.

Multiplying 0 is not a valid algebraic property, your theorem is invalid.

FAILED.

-------------

edit

Fuck I just realized how stupid it sounds. What Igir said is just dumb, but I think he knows what I know. Lemme try to explain it since I don't know the name of it. Basically, moving 1/0 = x to 1 = 0x is IMPOSSIBLE. You can never plug anything in for x that will equal one. You can't divide by zero in the first place, so moving it over is STILL INVALID.
DAVE x 0 = coackroach bish0dick suckin Arun

CORRECT

11. Originally Posted by KING
DAVE x 0 = coackroach bish0dick suckin Arun

CORRECT

12. lol teachers told us that we can just type NO ANSWER

13. Originally Posted by Alen
I know how to use a basic caculator

14. Originally Posted by KING
I know how to use a basic caculator
i know how to use a scinetistic (hope i got that word right)

15. Originally Posted by miki08

i know how to use a scinetistic (hope i got that word right)
ahhhaahaha

you mean scientific?

16. i leave the answer blank when i get that kind of problem.

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