Thread: Help me out

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  1. #1
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    Post Help me out

    Hey guys I need some help...

    Recently I was given a chance at extra credit on my final exam for math. The extra credit points could be very high, it's all determined by your grade. Basically what my teacher is doing is if you receive the extra credit he will take your highest simester average, subtract that from 100 and multiply it by 2.

    Example:
    (Highest average= 87; 100-87=13; 13x2=26; +26 extra credit)

    Anyways, to get this extra credit I need to find a math problem my teacher can't solve. If he can't solve it I have to provide the answer and a detailed explanation of how to get it.

    If you know of any math problems that could stump a highschool geometry teacher, could you please share?

    I will pick one, two at the most to use. If I do infact get the extra credit I will make you a sig, userbar, avatar, or nametag if you would like.


    For everyone who chooses to attempt to help me, thanks in advance.
    Last edited by Ryguy; 06-03-2009 at 03:00 PM.

  2. #2
    𝕡𝕠𝕔𝕜𝕖𝕥𝕤 𝕤𝕠 𝕗𝕒𝕥
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    arunforce's Avatar
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    Does Calculus count? :]



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  3. #3
    Czar's Avatar
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    Red face

    Tell him to prove this...
    If he can hes a genius [;
    Its the Goldbach Conjecture, ive done work with it before
    Link

    Goldbach's original conjecture (sometimes called the "ternary" Goldbach conjecture), written in a June 7, 1742 letter to Euler, states "at least it seems that every number that is greater than 2 is the sum of three primes" (Goldbach 1742; Dickson 2005, p. 421). Note that here Goldbach considered the number 1 to be a prime, a convention that is no longer followed. As re-expressed by Euler, an equivalent form of this conjecture (called the "strong" or "binary" Goldbach conjecture) asserts that all positive even integers >=4 can be expressed as the sum of two primes. Two primes (p,q) such that p+q=2n for n a positive integer are sometimes called a Goldbach partition (Oliveira e Silva).

    According to Hardy (1999, p. 19), "It is comparatively easy to make clever guesses; indeed there are theorems, like 'Goldbach's Theorem,' which have never been proved and which any fool could have guessed." Faber and Faber offered a $1000000 prize to anyone who proved Goldbach's conjecture between March 20, 2000 and March 20, 2002, but the prize went unclaimed and the conjecture remains open.

    Schnirelman (1939) proved that every even number can be written as the sum of not more than 300000 primes (Dunham 1990), which seems a rather far cry from a proof for two primes! Pogorzelski (1977) claimed to have proven the Goldbach conjecture, but his proof is not generally accepted (Shanks 1985). The following table summarizes bounds n such that the strong Goldbach conjecture has been shown to be true for numbers <n.
    bound reference
    1×10^4 Desboves 1885
    1×10^5 Pipping 1938
    1×10^8 Stein and Stein 1965ab
    2×10^(10) Granville et al. 1989
    4×10^(11) Sinisalo 1993
    1×10^(14) Deshouillers et al. 1998
    4×10^(14) Richstein 1999, 2001
    2×10^(16) Oliveira e Silva (Mar. 24, 2003)
    6×10^(16) Oliveira e Silva (Oct. 3, 2003)
    2×10^(17) Oliveira e Silva (Feb. 5, 2005)
    3×10^(17) Oliveira e Silva (Dec. 30, 2005)
    12×10^(17) Oliveira e Silva (Jul. 14, 2008)

  4. #4
    Ryguy's Avatar
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    Quote Originally Posted by arunforce View Post
    Does Calculus count? :]
    you can do anything you want :O

    Quote Originally Posted by Leonzfun View Post
    Tell him to prove this...
    If he can hes a genius [;
    Its the Goldbach Conjecture, ive done work with it before
    Link

    Goldbach's original conjecture (sometimes called the "ternary" Goldbach conjecture), written in a June 7, 1742 letter to Euler, states "at least it seems that every number that is greater than 2 is the sum of three primes" (Goldbach 1742; Dickson 2005, p. 421). Note that here Goldbach considered the number 1 to be a prime, a convention that is no longer followed. As re-expressed by Euler, an equivalent form of this conjecture (called the "strong" or "binary" Goldbach conjecture) asserts that all positive even integers >=4 can be expressed as the sum of two primes. Two primes (p,q) such that p+q=2n for n a positive integer are sometimes called a Goldbach partition (Oliveira e Silva).

    According to Hardy (1999, p. 19), "It is comparatively easy to make clever guesses; indeed there are theorems, like 'Goldbach's Theorem,' which have never been proved and which any fool could have guessed." Faber and Faber offered a $1000000 prize to anyone who proved Goldbach's conjecture between March 20, 2000 and March 20, 2002, but the prize went unclaimed and the conjecture remains open.

    Schnirelman (1939) proved that every even number can be written as the sum of not more than 300000 primes (Dunham 1990), which seems a rather far cry from a proof for two primes! Pogorzelski (1977) claimed to have proven the Goldbach conjecture, but his proof is not generally accepted (Shanks 1985). The following table summarizes bounds n such that the strong Goldbach conjecture has been shown to be true for numbers <n.
    bound reference
    1×10^4 Desboves 1885
    1×10^5 Pipping 1938
    1×10^8 Stein and Stein 1965ab
    2×10^(10) Granville et al. 1989
    4×10^(11) Sinisalo 1993
    1×10^(14) Deshouillers et al. 1998
    4×10^(14) Richstein 1999, 2001
    2×10^(16) Oliveira e Silva (Mar. 24, 2003)
    6×10^(16) Oliveira e Silva (Oct. 3, 2003)
    2×10^(17) Oliveira e Silva (Feb. 5, 2005)
    3×10^(17) Oliveira e Silva (Dec. 30, 2005)
    12×10^(17) Oliveira e Silva (Jul. 14, 2008)
    Problem + Explanation :O
    Last edited by Ryguy; 06-03-2009 at 03:02 PM.

  5. #5
    Czar's Avatar
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    Quote Originally Posted by Ryguy View Post
    you can do anything you want :O

    I was looking at this, seems difficult
    probability, global minimum, stuff like that..
    Link

    Explaining and proving the goldbach is currently one of the worlds un-solved math problems..
    just have your teacher try Lol.. people spend years trying

  6. #6
    mac_man's Avatar
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    (-2a^2+8a-4)-(8a^3-5a^2+3) you have to simplyfi
    =-2a^2+8a-4-8a^3+5a^2-3 simplyfi it again
    =-8a^3-2a^2+5a^2+8a-4-3 then simplyfi for the final answer
    =-8a^3+3a^2+8a-7 and that ur final answer

  7. #7
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    Quote Originally Posted by mac_man View Post
    (-2a^2+8a-4)-(8a^3-5a^2+3) you have to simplyfi
    =-2a^2+8a-4-8a^3+5a^2-3 simplyfi it again
    =-8a^3-2a^2+5a^2+8a-4-3 then simplyfi for the final answer
    =-8a^3+3a^2+8a-7 and that ur final answer
    Lol epic fail.

  8. #8
    𝕡𝕠𝕔𝕜𝕖𝕥𝕤 𝕤𝕠 𝕗𝕒𝕥
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    Is you're teacher reasonably smart? I can write a simple question, or a hard question.



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  9. #9
    Empire's Avatar
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    -_- leonz, if he can't provide the answer to the goldbach, then he can't use it. It has to be a problem with a answer he can provide.


  10. #10
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    Mathematics - Wikipedia, the free encyclopedia

    Learn what you think you can.

  11. #11
    Ryguy's Avatar
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    Quote Originally Posted by arunforce View Post
    Is you're teacher reasonably smart? I can write a simple question, or a hard question.
    Uhm

    Yea hes pretty smart :O


    And he's one of those people who even if he doesnt get it will spend time on the problem for a very long time until he gets it

  12. #12
    XxeekXx's Avatar
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    This question will rattle him
    How many fail projects has Jetamay worked on

  13. #13
    Ryguy's Avatar
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    Hurry I need it by tomorrow :O

  14. #14
    Alen's Avatar
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    Ok, I'm gonna dig up some competion stuff I got as prep. Give me 10 mins to find a problem & translate.

    EDIT: got some junk, but it's easy to solve once you see the trick. Let me find some state level junk.

    EDIT2: can't find the state junk, got some regional levels, what you want, geometry, algebra...?
    Last edited by Alen; 06-04-2009 at 03:04 PM.
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    Anything a highschool geom teacher couldnt figure out

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