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  1. #16
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    Quote Originally Posted by Lehsyrus View Post


    No. The amount of moles of any given molecule is directly correlating to the number of grams in a substance. 3NaHCO3 is 23 NA, 1 H, 12 C, 16 * 3 O, all multiplied by 3. So that is 252. 3CO2 is (12+32)*2 which is 88. One Mole of NAHCO3 is 84. One Mole of CO2 is 44.
    Yes, but the numbers in front of the molecules, like the 3 before CO2 and 3 before NaHCO3 are stehiometric coefficients and I believe that means that if there's 5 moles of NaHCO3, then there's 5 moles of CO2.

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    It was probably in excess so not all reacted.

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    hate it and the maths....









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    Quote Originally Posted by Wolf View Post
    It was probably in excess so not all reacted.
    That's after excess. I have 0,0085 mol NaHCO3, 0,017 mol C6H8O7 and it produces 0,0035 mol CO2. The NaHCO3 and C6H8O7 are sorted so none is in excess. Now considering the stehiometric coefficients, the amount of CO2 in moles should be equal to amount of NaHCO3 -> 0,0085 mol.

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    I'm going to be starting chemistry soon, man I have so much studies to do...

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    oh gosh anorganic chemistry and me.
    organic chemistry ftw
    Felicior Augusto, melior Traiano

  7. #22
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    Quote Originally Posted by Domen View Post

    Yes, but the numbers in front of the molecules, like the 3 before CO2 and 3 before NaHCO3 are stehiometric coefficients and I believe that means that if there's 5 moles of NaHCO3, then there's 5 moles of CO2.
    I read the question wrong, I was thinking grams when I said no. The relative number of moles is the same, however the number of grams in each mole is different. So technically speaking, yes, the mole count is equivalent.

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