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  1. #31
    Chuck_Noris's Avatar
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  2. #32
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    i finally get it and now my head hurts

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  3. #33
    Aborted's Avatar
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    You're literally just adding 7+7+7 (which IS 7x3) with half of a dozen completely unneeded additions and subtractions.
    You're a fucktard.
    I am the seer in the dark,
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    valediction.
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    my form now vivid,
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  5. #34
    𝕡𝕠𝕔𝕜𝕖𝕥𝕤 𝕤𝕠 𝕗𝕒𝕥
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    He's not expressing the usefulness of his theory for solving simple equations, he's expressing that it can be used for other equations. Which is true, STEM majors use secondary mathematical relations to solve things when normal methods don't work.

    On the other hand, here's your theory using variables.

    x*y = a where x > y:

    (x+y)+(x-y)=z
    z+x*(y-2)=a

    Simplify that equation and tell me what you get.
    Last edited by arunforce; 03-08-2014 at 05:11 PM.



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  6. #35
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    Hmm i get it... But its quite complicate and time consuming, better off just remember ur timetables by head but i guess this does help in some situations.

  7. #36
    HeyWASSUP's Avatar
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    Math is not my thing

  8. #37
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    I don't think this is a theory, more of a formula.

  9. #38
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    understood first time not really complex, and your not the first google it

  10. #39
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    Quote Originally Posted by Mayion View Post


    Video?
    A LEECHER IS A LEECHER EVEN IN MATH.
    Sorry ya @Mayion
    I still don't get it.
    Support me.

  11. #40
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    Quote Originally Posted by arunforce View Post
    He's not expressing the usefulness of his theory for solving simple equations, he's expressing that it can be used for other equations. Which is true, STEM majors use secondary mathematical relations to solve things when normal methods don't work.

    On the other hand, here's your theory using variables.

    x*y = a where x > y:

    (x+y)+(x-y)=z
    z+x*(y-2)=a

    Simplify that equation and tell me what you get.
    x*y = a where x > y:

    (x+y)+(x-y)=z
    z+x*(y-2)=a

    You're simply getting two numbers like 7(x)*3(y) = 21(a)
    And then you complete it with (-+) (The first result comes) and after that you actually add the x to the z (14(z)+7(x))= 21 and after that you add the sevens as many numbers it gets added , I mean If It was 3 it would be y-2 , If it was 4 it would be y-3 etc... And after you make it minus the y It becomes 1 and you actually get the result.

    You're actually doing the last step wrong because it won't work with all equations and/or numbers , the right one:
    x * y = a
    (x + y) + (x - y) = z
    (z+(x*(y - 2))) = a

  12. #41
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    Quote Originally Posted by Poison View Post
    understood first time not really complex, and your not the first google it
    I didn't google it , Not because you suck in maths means all sucks.

    Quote Originally Posted by Leosanity View Post
    Hmm i get it... But its quite complicate and time consuming, better off just remember ur timetables by head but i guess this does help in some situations.
    Do you know why equations exist?

    Quote Originally Posted by Aborted View Post
    You're literally just adding 7+7+7 (which IS 7x3) with half of a dozen completely unneeded additions and subtractions.
    You're a fucktard.
    Yes , I'm a fucktard . Learn to read , metaldick. The same comment up there. Do you know why equations exist?
    I don't fucking post it to calculate 7*4 or 5*2 what shit is it.

  13. #42
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    This theory is actually useless...


    for the 7*3:
    say: x * y
    what you're saying is x*y = x + (x-y) + (x+y)
    this is obviously not true, you can just simplify the second equation to see this.
    x+x-y+x+y
    so pretty much you just did extra work to find that 3 * x... which means 3 * 7 = 21.

    for anything * 2
    say : x*y
    x*y = (x-y) + (x+y)
    x-y+x+y = 2*x
    Which is the exact same thing as original
    and its not an "equation" if you have to do different operations every time...
    Last edited by killzone553; 03-09-2014 at 07:39 AM.

  14. #43
    𝕡𝕠𝕔𝕜𝕖𝕥𝕤 𝕤𝕠 𝕗𝕒𝕥
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    Quote Originally Posted by Muntailor View Post

    x*y = a where x > y:

    (x+y)+(x-y)=z
    z+x*(y-2)=a

    You're simply getting two numbers like 7(x)*3(y) = 21(a)
    And then you complete it with (-+) (The first result comes) and after that you actually add the x to the z (14(z)+7(x))= 21 and after that you add the sevens as many numbers it gets added , I mean If It was 3 it would be y-2 , If it was 4 it would be y-3 etc... And after you make it minus the y It becomes 1 and you actually get the result.

    You're actually doing the last step wrong because it won't work with all equations and/or numbers , the right one:
    x * y = a
    (x + y) + (x - y) = z
    (z+(x*(y - 2))) = a
    That is the exact same equation...

    Anyways, the point of this whole thing is if you simplify the first step, it's exactly the same as 2x, and you're just tacking on the remainder through addition. You're essentially doing nothing with the first step because adding a positive difference and negative difference is ZERO.

    If you simplify the equation, you would get 2x+x*(y-2)= a, which can be simplified even more to x*y=a

    So it's not a "new theory," it's just playing with numbers.



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  15. #44
    KaptainKracker's Avatar
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    Calculators ftw

  16. #45
    Express.'s Avatar
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    Finally understood a little after I read it like 2-3 times, not bad.
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