# Thread: Fast and Furious 6 Question

1. ## Fast and Furious 6 Question

K so I'm not sure how many of you guys have seen Fast and Furious 6, but there's this one scene where Mr. Beautiful Handsome Rock jumps from one a moving car to another moving car below him.

This is a thread for people with some decent physics knowledge and that actually uses their brain every so often, so please don't comment if you have no idea what you're talking about.

Please keep in mind the velocities of both cars, and that air resistance is taken into account. As well it's centripetal acceleration (since it's somewhat curved).

Any proof you provide along the way is nice too.

Keep in mind the road is slightly curved.

How many of you guys think he won't land on the car. That's crazy, he will fly back a lot further.

And how many of you guys think he will land on the car. Yes, he will land.

NOTE: You don't have to do this, just want to know your opinions.

If you are one that likes being rewarded, a free +rep and thanks are always nice.

2. No he won't land inside the car, only because the road is curved makes it almost impossible to just (like him) do it without thinking about it before. Also the car their speed need to be calculated and that will never ever work without calculating at least something. It's a movie for something I guess.

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KingDot (03-23-2014)

4. Logically he won't. In the trailer however he does. Why won't he land? Well if you actually do a bit of math and physics you'll find out that he isn't heavy enough to land on time. Car is moving way too fast, he needs to weigh atleast like 200 pounds? Anyway if it were in real life it'd be a 100% death wish. It needs time to calculate and perform accurately..
oh and welcome back

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KingDot (03-23-2014)

6. Originally Posted by DarkLordXYZ
Logically he won't. In the trailer however he does. Why won't he land? Well if you actually do a bit of math and physics you'll find out that he isn't heavy enough to land on time. Car is moving way too fast, he needs to weigh atleast like 200 pounds? Anyway if it were in real life it'd be a 100% death wish. It needs time to calculate and perform accurately..
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OK, so… wait, let me see if I understand this....so if he was heavier, he would fall faster?

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KingDot (03-23-2014)

8. Yes, because he's the goddamn Rock, and doesn't give a damn what your candy ass thinks.

Also 15 minute runway. Nuff said.

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KingDot (03-23-2014),Symboliq (03-24-2014)

10. Originally Posted by DarkLordXYZ
Logically he won't. In the trailer however he does. Why won't he land? Well if you actually do a bit of math and physics you'll find out that he isn't heavy enough to land on time. Car is moving way too fast, he needs to weigh atleast like 200 pounds? Anyway if it were in real life it'd be a 100% death wish. It needs time to calculate and perform accurately..
oh and welcome back
You do know that Dwayne Johnson weighs 262 pounds don't you? Either way, it's not impossible but rather extremely impractical to jump on this car at those speeds anyway.

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KingDot (03-23-2014)

12. I'm sorry to the psuedo-physicists above me, but yes this is indeed plausible, not absolute, but plausible.'It's virtually impossible to make an exact conclusion based on our ignorance of:
The height he fell.
His exact mass and weight.
The air resistance enacted on his mass.
The velocity AND accleration of the lower car.
The velocity AND acceleration of the upper car.
And the mass and weight of the upper car.

By Newton's first law and the concept of inertia, if the upper vehicle were travelling at 60 ***, he would exit the car at the same speed, added to his horizontal velocity from jumping. Due to his lower air resistance, he would cover far more air ground from this residual forward velocity than a boxy vehicle. The issue that arises is that his due to his mass being far lower, he carries less inertia, though this is counteracted by his lower air resistance.

An absolutely perfect example is something I learned in College, with a ball launched from a moving cart.

As you can see, though its mass is much lower, it maintains a forward velocity exactly consistent with the cart, allowing it end in the exact same relative location. Expanding on this, if you were to jump directly upwards off a moving car, you would once again land on the car's roof. Though due to the horizontal/diagonal velocity added in this case, the jumper would gather even more momentum to propel him toward his target. If 2 cars are parallel and travelling at the same velocity, he would land in precisely the same spot the car he jumped from would've been, just about 10 feet to the left.

In my opinion, yes, this is entirely possible.

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KingDot (03-23-2014)

14. Yea, it is possible when jumps out he would be moving at the same speed of the car he was in and it is a little further the the lower car

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KingDot (03-23-2014)

16. Theoretically speaking, yes. It's a simple conceptual physics, really.

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KingDot (03-23-2014)

18. Originally Posted by Aborted
I'm sorry to the psuedo-physicists above me, but yes this is indeed plausible, not absolute, but plausible.'It's virtually impossible to make an exact conclusion based on our ignorance of:
The height he fell.
His exact mass and weight.
The air resistance enacted on his mass.
The velocity AND accleration of the lower car.
The velocity AND acceleration of the upper car.
And the mass and weight of the upper car.

By Newton's first law and the concept of inertia, if the upper vehicle were travelling at 60 ***, he would exit the car at the same speed, added to his horizontal velocity from jumping. Due to his lower air resistance, he would cover far more air ground from this residual forward velocity than a boxy vehicle. The issue that arises is that his due to his mass being far lower, he carries less inertia, though this is counteracted by his lower air resistance.

An absolutely perfect example is something I learned in College, with a ball launched from a moving cart.

As you can see, though its mass is much lower, it maintains a forward velocity exactly consistent with the cart, allowing it end in the exact same relative location. Expanding on this, if you were to jump directly upwards off a moving car, you would once again land on the car's roof. Though due to the horizontal/diagonal velocity added in this case, the jumper would gather even more momentum to propel him toward his target. If 2 cars are parallel and travelling at the same velocity, he would land in precisely the same spot the car he jumped from would've been, just about 10 feet to the left.

In my opinion, yes, this is entirely possible.
Haha, that's what I was trying to get at. Been trying to explain it to someone for a while, but they're pretty sure it's not plausible.

Thanks for actually putting some time into your answer. Not saying others didn't, but the video helped. Thanks babe. Glad to see you still rocking.

Originally Posted by arunforce
Yes, because he's the goddamn Rock, and doesn't give a damn what your candy ass thinks.

Also 15 minute runway. Nuff said.
Arun that was bootiful.

19. He would never make it. Then the 107472 mile long runway and when dom jumps over the highway to save letty. Just no.

20. Well here's the actual question. Why does rock need to jump to that car? Why can't he pull out a RPG because last time I remembered a fucking question isn't asked when an RPG-7 is discharged.

21. I think you guys will find that the Rock is stationary the entire time, and he is just command the Earth to move accordingly. Such is the greatness of Lord Dwayne Johnson.

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Aborted (03-24-2014)