# Thread: Maths Question - Help me D:

1. ## Maths Question - Help me D:

OKay so here's the dealio. I have an exam on Thursday and I've been doing past papers etc. for revision and then I came upon this question:

I'm focusing on 9ii

So firstly, you re-arrange loga^5 + loga you get 5loga + 0.5loga
and logx + logy = logxy if I'm correct, so surely it should be 5.5loga^2? but apparently it's just 5.5loga
then you divide by loga and the answer is supposed to be just 5.5
I feel insanely stupid right now, so you can flame.

If anyone can explain/help me out I'd be very grateful ^.^

It's some simple shit yeah, but it's confusing the hell out of me and I have an exam Thursday so I want everything to be crystal clear.
Nerds assemble!
Thank you ;D

2. Hold up, is it because they're both in loga that I can add them?
so say if it's 5logx+2logy it doesn't = 7logxy, but instead log(x^5)/(y^2)?
but if it's 5logx+2logx it does = 7logx?

3. Homework section is still a thing right? Why are you posting it here?

4. Originally Posted by Domokun_index
Hold up, is it because they're both in loga that I can add them?
One mistake you made is when adding 5loga + 0.5loga and getting 5.5loga^2, as a is now an unchangeable part of the variable, rather than a simple multiplicand. Think of logA as a group in itself, you have 5 logA's + .5 logA's, and you end with 5.5 logA's. logx + logy is NOT logxy as logx and logy are unlike terms, and can not be added, while both in this ARE like terms, in logA. Remember, you are adding, not multiplying.

Then you simply cancel the 5.5logA with the logA in the denominator, and end with a raw 5.5

5.5logA
----------
logA

=
5.5

5. ## The Following User Says Thank You to Aborted For This Useful Post:

Domokun_index (06-05-2014)

6. 5.5 looks correct to me, I don't know if that's your answer or not, but the math adds up.

7. Originally Posted by Metamyota
Homework section is still a thing right? Why are you posting it here?
Homework section is dead. No body ever gets a reply within a reasonable amount of time.

8. Originally Posted by Doc

Homework section is dead. No body ever gets a reply within a reasonable amount of time.
Oh, alright. Fuck man, I remember when it was actually active.

9. Originally Posted by Domokun_index
OKay so here's the dealio. I have an exam on Thursday and I've been doing past papers etc. for revision and then I came upon this question: ...
Thank me yo

Did it on foolscap and here's the working ...

10. ## The Following 2 Users Say Thank You to Ygritte For This Useful Post:

Domokun_index (06-05-2014),Sazyrus (06-05-2014)

11. Originally Posted by Aborted

One mistake you made is when adding 5loga + 0.5loga and getting 5.5loga^2, as a is now an unchangeable part of the variable, rather than a simple multiplicand. Think of logA as a group in itself, you have 5 logA's + .5 logA's, and you end with 5.5 logA's. logx + logy is NOT logxy as logx and logy are unlike terms, and can not be added, while both in this ARE like terms, in logA. Remember, you are adding, not multiplying.

Then you simply cancel the 5.5logA with the logA in the denominator, and end with a raw 5.5

5.5logA
----------
logA

=
5.5
Thank you sir for the insight and explanation.
My teacher kind of sucks and doesn't cover things well (he got 60.1% which is .1% into two firsts on his degree so we basically have the worst kinda teacher you can get)

Originally Posted by Avril Lavigne+

Thank me yo

Did it on foolscap and here's the working ...
That's a good way of looking at it, thank you ^.^