# Thread: In Need Of a Asian :)

1. ## In Need Of a Asian :)

I need someone to explain this nonsense to me

Is that right? And if it is can you explain it to me.

Don't be a Dix i'm trying to study for a math test tomorrow and i'm failing math at the moment. Help a nigga out

I might have more questions if someone is good at this.

2. Are you in 7th grade or some shit?

It's the sin rule.

sin90 x sin62
___________ = Your answer, something similar anyways, may be sin90 x 7.2 tho, I don't remember, been years since I did this shit.
7.3

3. Nope, it's 6.4 use law of sines.

a/sinA=b/sinB=c/sinC
C=90 degrees
B=62 degrees
side b=7.3

so,

7.3/sin62=x/sin90

isolate x by multiplying sin90

x=(7.3/sin62)(sin90)
x=6.4

4. ## The Following User Says Thank You to Shane For This Useful Post:

FlexGod (10-23-2014)

5. Originally Posted by Shane
Nope, it's 6.4 use law of sines.

a/sinA=b/sinB=c/sinC
C=90 degrees
B=62 degrees
side b=7.3

so,

7.3/sin62=x/sin90

isolate x by multiplying sin90

x=(7.3/sin62)(sin90)
x=6.4
How do i tell when to use cos sin or tan depending on the triangle?

And could you type it how you would put it in a caculator or a TI-30XIIS to be specific

6. Originally Posted by Scotia
Are you in 7th grade or some shit?
I'm grade 11 and i still take these stuff.
------
OT: I'll search for the rules.

7. ## The Following User Says Thank You to Mayion For This Useful Post:

FlexGod (10-23-2014)

8. Originally Posted by Mayion

I'm grade 11 and i still take these stuff.
------
OT: I'll search for the rules.
It's the sin rule, no need to search it up.

9. Originally Posted by flex1178
How do i tell when to use cos sin or tan depending on the triangle?

And could you type it how you would put it in a caculator or a TI-30XIIS to be specific
In this type of situation there is no need to use cos or tan because it's law of sines, but if you're asking when you wanna use sin cos and tan, it's only when you have a right triangle: 90 degrees.

sin: opposite/hypotenuse

(using Pythagorean theorem to find hypotenuse)

10. ## The Following User Says Thank You to Shane For This Useful Post:

[MPGH]Mayion (10-23-2014)

11. Originally Posted by Shane

In this type of situation there is no need to use cos or tan because it's law of sines, but if you're asking when you wanna use sin cos and tan, it's only when you have a right triangle: 90 degrees.

sin: opposite/hypotenuse

(using Pythagorean theorem to find hypotenuse)
7.3/sin(62)sin(90)
When i enter that every time i get 8.26 which rounds up to 8.3
Obviously i'm wrong but how do I fix it?

12. You can just use logic to answer this question... The highest degree side will be the longest. The right angle is = 90 degrees. The 7.3 is 62 degrees. 90 + 62 = 152. 180 - 152 = 28. The third degree is 28. This means the longest side will correspond to the 90 degree. This makes it longer than 7.3 so 8.3 is you only possible answer.

13. SOHCAHTOA motherfucker.
Sine opposite Hypotenuse

14. ## The Following User Says Thank You to Aborted For This Useful Post:

Oliboli8769 (10-23-2014)

15. Originally Posted by Aborted
SOHCAHTOA motherfucker.
Sine opposite Hypotenuse
He would need the lengh of 2 sides for that, he only has 1 side along with 2 angles, meaning it's the sin rule.

Aborted got a maths question wrong? Witchcraft.

16. Originally Posted by Scotia

He would need the lengh of 2 sides for that, he only has 1 side along with 2 angles, meaning it's the sin rule.

Aborted got a maths question wrong? Witchcraft.
I never even looked at the diagram, just the question asking for the length of side AB.
Of course it's the law of sines if you have 2 angles and a side, it's the direct inverse.

Edit: Looked at the diagram, and yeah it's law of sines, but your equation is incorrect.
sin62 goes over 7.3, not sin90
It's the side opposite, not adjacent.

sin90 = sin62
-------- ...-------
x ......... 7.3

17. ## The Following 3 Users Say Thank You to Aborted For This Useful Post:

FlexGod (10-23-2014),Oliboli8769 (10-24-2014),Scotia (10-23-2014)

18. Originally Posted by Aborted

I never even looked at the diagram, just the question asking for the length of side AB.
Of course it's the law of sines if you have 2 angles and a side, it's the direct inverse.

Edit: Looked at the diagram, and yeah it's law of sines, but your equation is incorrect.
sin62 goes over 7.3, not sin90
It's the side opposite, not adjacent.

sin90 = sin62
-------- ...-------
x ......... 7.3

Got 6.4

So First i enter sin and the 2 angles then multiply it by the one side and wala?

19. Originally Posted by Scotia
Are you in 7th grade or some shit?

It's the sin rule.

sin90 x sin62
___________ = Your answer, something similar anyways, may be sin90 x 7.2 tho, I don't remember, been years since I did this shit.
7.3
You better be Asian, OP was very specific >.<

20. Originally Posted by flex1178
Got 6.4

So First i enter sin and the 2 angles then multiply it by the one side and wala?
Oh shit, formatting got jacked up.
Should be side length over angle, not angle over side length.

...x .........7.3
.----- ...= -----
sin90 ..sin62

We are solving for x, so we need to isolate it from the rest of the equation.
To do that, we multiply both sides by sin90, which results in:

x= (7.3/sin62)sin90

The sine of 90 is always 1, so the inside of our parentheses stays the same.

Now we solve.
sin62= 0.88294

7.3/0.88294 = 8.3

x=8.3

There you have it