1. ## Algebra solver about ((x-8)/(6))^(2)-2((x-8)/(6))+1=0

there is an algebra math question. Look at the function: ((x-8)/(6))^(2)-2((x-8)/(6))+1=0. Please calculate it for me. can anyone help me? Thanks a lot.

2. @Alen Or @Shunnai it's doesn't go into warrock
So Close.

3. /Moved to help and requests

4. Yeah wrong help and request section

5. ## The Following User Says Thank You to Keroaplt For This Useful Post:

ARHQA\$Y\$YW4AYG4y (10-28-2011)

6. Wrong section.

((x-8)/(6))^(2)-2((x-8)/(6))+1=0
(x/6)^2-(8/6)^2-2(x/6-8/6)+1=0
x^2/36-64/36-2(x-8/6)+1=0
x^2-64/36-(2x-16/6)+1=0
x^2-64-12x-96/36+1=0
x^2-12x-160/36+1=0
x.x-12x-60/36+1=0

I don't know further...

7. @memjess result here
Dunno if correct (until that phrase its correct)

8. ## The Following User Says Thank You to Occidi de Pax For This Useful Post:

ARHQA\$Y\$YW4AYG4y (10-28-2011)

9. Originally Posted by memjess
there is an algebra math question. Look at the function: ((x-8)/(6))^(2)-2((x-8)/(6))+1=0. Please calculate it for me. can anyone help me? Thanks a lot.
Algebra solver about ((x-8)/(6))^(2)-2((x-8)/(6))+1=0 for a sophmore student. -BidAnswer.com Fast helps for all your questions.
The "simple" way to do it, hope I didn't make any trivial mistakes:

Originally Posted by Chuck
Wrong section.

((x-8)/(6))^(2)-2((x-8)/(6))+1=0
(x/6)^2-(8/6)^2-2(x/6-8/6)+1=0
x^2/36-64/36-2(x-8/6)+1=0
x^2-64/36-(2x-16/6)+1=0
x^2-64-12x-96/36+1=0
x^2-12x-160/36+1=0
x.x-12x-60/36+1=0

I don't know further...
You can't do this ...

Derp:

Originally Posted by ultimateon
@memjess result here
Dunno if correct (until that phrase its correct)
https://gyazo.com/4187cc95ea6db85fcd84371bc5a2f689.png
Derp 2:

10. ## The Following User Says Thank You to Alen For This Useful Post:

Lehsyrus (10-29-2011)

11. You must be kidding...

I'm too lazy to type out the answer. But here is WolframAlpha's answer:

12. Originally Posted by Alen
The "simple" way to do it, hope I didn't make any trivial mistakes:

You can't do this ...

Derp:

Derp 2:

A fuck I failed. We didn't even come to that in maths. We're at advanced potentions...

What grade are you? I'm freshman gymnasium...

13. Originally Posted by Chuck
A fuck I failed. We didn't even come to that in maths. We're at advanced potentions...

What grade are you? I'm freshman gymnasium...
Last year of IB, though this is supposed to be like 1st / 2nd year gymnasium stuff

14. Originally Posted by Alen
The "simple" way to do it, hope I didn't make any trivial mistakes:

You can't do this ...

Derp:

Derp 2:

I noticed a mistake. You need to distribute the 2 before being able to close it as variable l, but at that point the numerical digits change along with the value of x.

((x-8)/(6))^(2)-2((x-8)/(6))+1=0

((x-8)/(6))^(2)+((-2x+16)/(-12))+1=0

Both ways still work however, I don't feel like writing out the rest of my math as I haven't had to worry about math in a couple of years and it hurts my head.

15. Originally Posted by Lehsyrus
I noticed a mistake. You need to distribute the 2 before being able to close it as variable l, but at that point the numerical digits change along with the value of x.

((x-8)/(6))^(2)-2((x-8)/(6))+1=0

((x-8)/(6))^(2)+((-2x+16)/(-12))+1=0

Both ways still work however, I don't feel like writing out the rest of my math as I haven't had to worry about math in a couple of years and it hurts my head.
Err, not sure what you're trying to say but the value of x remains constant all the time and

16. Originally Posted by Alen
Err, not sure what you're trying to say but the value of x remains constant all the time and
My bad I was thinking of another way to solve the problem.

17. Originally Posted by Lehsyrus

My bad I was thinking of another way to solve the problem.
Actually fuck that, I accidentally forgot to copy & paste the -2 you wrote. Lazy me.

But yeah, what I wrote was (if you noticed the slight typo) right.

18. Originally Posted by Alen
Actually fuck that, I accidentally forgot to copy & paste the -2 you wrote. Lazy me.

But yeah, what I wrote was (if you noticed the slight typo) right.
True true, just a shorthand method, I always seem to take the longer ways to solve problems