New method bypass client error 28_3 and 31_0, shorter :D

[ronjeffrey123]

U should download Visual Studio 2008 or 2010 or 2017 anyone and create a Win32 Project then u select DLL and write the code. Finaly u compile it and inject it!

Video Tutorial:
That should work!

If i help u give me thanks and rep me!

sir i dont know how to use the code sorry for my english 2nd lang... sir can you send it to me in facebook.com/RonjeffreyCF the application of the bypass

[mattstm]

What is your CF?
I need it to do the bypass.
If its CF PH i think thast u can use that tutorial for xTrap:

If it solves give Thanks!

[codex1992]

i already try this method but 28_4 always appear after few minutes...... anyone can help me how to bypass 28_4 hmmmmm

[mike123456mike]

This bypass is the shortest, i think
Bypass 28_3:

Pattern: 83 F8 FF 0F 84 ?? ?? ?? ?? 56 50 E8
105D1C2A      | 83 F8 FF                 | cmp eax,-01                             |
105D1C2D      | C7 44 24 14 00 00 00 00  | je 105D1E2A                             |
105D1C33      | 56                       | push esi                                |
105D1C34      | 50                       | push eax                                |
105D1C35      | E8 86 CD DB FF           | call 1038E9C0                           | -> function called to check
105D1C3A      | 8B F0                    | mov esi,eax                             |
105D1C3C      | 83 C4 04                 | add esp,04                              |
105D1C3F      | 85 F6                    | test esi,esi                            |
105D1C41      | 0F 84 E2 01 00 00        | je 105D1E29                             | He's here, now change je -> jmp
105D1C4D      | D9 86 58 10 00 00        | fld dword ptr [esi+00001058]            |
105D1C54      | 0F B6 86 BC 0B 00 00     | movzx eax,byte ptr [esi+00000BBC]       |

Bypass 31_0:

Pattern: 53 50 8B 42 2C FF D0
105D261E      | 83 C4 08                 | add esp,08                              |
105D2621      | 85 C0                    | test eax,eax                            |
105D2623      | 74 48                    | je 105D266D                             | He's here, change into "jmp 105D2637 + 4F"
105D2625      | 8B 0D A4 4F C0 10        | mov ecx,[10C04FA4]                      |
105D262D      | 8B 11                    | mov edx,[ecx]                           |
105D2631      | 8D 5C 24 10              | lea ebx,[esp+10]                        |
105D2636      | 05 70 17 00 00           | add eax,00001770                        |
105D2637      | 53                       | push ebx                                | -> Search return here. Value=105D2637+4F
105D2638      | 50                       | push eax                                |
105D1C54      | 8B 42 2C                 | mov eax,[edx+2C]                        |
.....////.... |                          |                                         |
105D2637 + 4F | 5F                       | pop edi                                 |

Have fun! Thanks if i helped!

How do you apply the code though?

[vaisefud3]

How do you apply the code though?

Why the actual fuck would you ask this in a 3 year old thread