Math problem

[SirusFPS]

Can anyone please explain to me how to solve sin(x)= -1 where the possible solutions for the angle is between 0 and 4pi ? i.e not in between 0 and 360 degrees?

[SuchAPirate]

x = arc sin (-1 )

[SirusFPS]

x = arc sin (-1 )

Doesn't that just give the reference angle though? which would only work for angles between 0 and 2pi?

[SuchAPirate]

That is the only way to solve it @SirusFPS

[SirusFPS]

That is the only way to solve it @SirusFPS

i drew the graph out, so i got 2 solutions X1 = arcsin (-1) + pi and X2 = arcsin (-1) +3pi

so X1 = 3pi/2 and X2 = 7pi/2

[[MPGH]Hero]

Can anyone please explain to me how to solve sin(x)= -1 where the possible solutions for the angle is between 0 and 4pi ? i.e not in between 0 and 360 degrees?

sin(x) = -1 if x = 2pi*n + (3/2)*pi, where n = 0, 1, 2, 3, ....
so in the range of 0 to 4pi, your only answers here are (3/2)*pi and (7/2)*pi.

[SirusFPS]

sin(x) = -1 if x = 2pi*n + (3/2)*pi, where n = 0, 1, 2, 3, ....
so in the range of 0 to 4pi, your only answers here are (3/2)*pi and (7/2)*pi.

thank you, that makes sense to me!

[[MPGH]Hero]

thank you, that makes sense to me!

np, if you are a bit confused still or on anything else math related, post a message on my profile.