C++ LPWSTR

[aanthonyz]

How will I be able to read the contents of a LPWSTR?

hr = pPhrase->GetText(SP_GETWHOLEPHRASE, SP_GETWHOLEPHRASE, FALSE, &pwszText, 0);
	 std::wcout << pwszText << " (" << pParts->Rule.ulId << ") " << std::endl;

This is for Speech Recognition. What the user says gets stored in pwszText, is there a way I can read it?

Lets say it says "Run Firefox"
Can I make C++ read that and then execute a command depending on what pwszText contains?

[Hell_Demon]

strwcmp? :3

[aanthonyz]

This solved my problem:

hr = pPhrase->GetText(SP_GETWHOLEPHRASE, SP_GETWHOLEPHRASE, FALSE, &pwszText, 0);
	 USES_CONVERSION;
	 char * s =(W2A(pwszText));
	 if(strcmp(s,"run Fire Fox") == 0)
	 {std::cout << "It worked!\n";}

[freedompeace]

This solved my problem:

hr = pPhrase->GetText(SP_GETWHOLEPHRASE, SP_GETWHOLEPHRASE, FALSE, &pwszText, 0);
	 USES_CONVERSION;
	 char * s =(W2A(pwszText));
	 if(strcmp(s,"run Fire Fox") == 0)
	 {std::cout << "It worked!\n";}

But if I type it correctly, "run Firefox", it'll fail.

do you see a design flaw there?

This solved my problem:

hr = pPhrase->GetText(SP_GETWHOLEPHRASE, SP_GETWHOLEPHRASE, FALSE, &pwszText, 0);
	 USES_CONVERSION;
	 char * s =(W2A(pwszText));
	 if(strcmp(s,"run Fire Fox") == 0)
	 {std::cout << "It worked!\n";}

But if I type it correctly, "run Firefox", it'll fail.

do you see a design flaw there?

[aanthonyz]

My program is specifically designed to only recognize it like this:

run Fire Fox

[coolcid]

Well do you have a couple of specific kommands?
One thing you can do is have a menu come up simply stating

1=Run furefox
2=xx
3=xx

Then have the user just input a 1,2,3.

I beileve C++ is picky on capped or uncapped variables so I don't know how to tell you how to, unless you have Run Firefox, run firefox, Run FireFox and you know, variations all do the same thing.

[aanthonyz]

My program only runs on voice, so I dont use cin at all