C++ modifying variables from outside main()

[utherson601]

i was wondering how to modify the following to make the loop end without using "return".
in otherwords im asking how to use "meow()" to directly edit "main()"s int1

void meow(int int1)
{
	int1 += 10;
	cout << int1 << endl;
}


int main()
{
	int int1 = 5;
	while(int1 < 100)
	{
	meow(int1);
	}

   system("pause");
    return 0;
}

[radnomguywfq3]

i was wondering how to modify the following to make the loop end without using "return".
in otherwords im asking how to use "meow()" to directly edit "main()"s int1

void meow(int int1)
{
	int1 += 10;
	cout << int1 << endl;
}


int main()
{
	int int1 = 5;
	while(int1 < 100)
	{
	meow(int1);
	}

   system("pause");
    return 0;
}

Use a reference.

void meow(int& int1)
{
	int1 += 10;
	cout << int1 << endl;
}


int main()
{
	int int1 = 5;
	while(int1 < 100)
	{
	meow(int1);
	}

   system("pause");
    return 0;
}

You can also use a pointer (less desired method in C++, but only method in C):

void meow(int* int1)
{
	*int1 += 10;
	cout << *int1 << endl;
}


int main()
{
	int int1 = 5;
	while(int1 < 100)
	{
	meow(&int1);
	}

   system("pause");
    return 0;
}

However, this deafeat the purpose of a function, which is to be more or less self-contained. Rarely should you use references in this sort of context.

[utherson601]

thanks, i almost gave up on trying to do it..... i really need to remember this ....