do my stats hw ill pay you 5$ its only 1 problem and im to lazy to do it

[Poison]

70% of residents have reduced their electricity usage sufficiently to qualify for discounted rates. If 5 residential subscribers are randomly selected A. What is the probability that all five qualify for the discounted rates B.find the probability that at least 4 qualify c. Find the probability that most of the residents qualify Show work And please show steps

[Hachikuji]

a. (.70)^5 = 0.16807

b. (.70)^4 * (.70)^5 = 0.117649

c. assuming that most = 3

(.70)^3 = 0.343

not sure if right but whatever

[Farting Scum]

a. (.70)^5 = 0.16807

b. (.70)^4 * (.70)^5 = 0.117649

c. assuming that most = 3

(.70)^3 = 0.343

not sure if right but whatever

Then don't answer

[Poison]

you only get the money if your right

[Poison]

6 hours left untill i close

[exodoS_]

42?

(2^2 + 2) * (24/3 - 99^0)
= 42

"Answer to The Ultimate Question of Life, the Universe, and Everything"

I guess I win GG WP

[Niku ・(￣∀￣)・]

70% of residents have reduced their electricity usage sufficiently to qualify for discounted rates. If 5 residential subscribers are randomly selected A. What is the probability that all five qualify for the discounted rates B.find the probability that at least 4 qualify c. Find the probability that most of the residents qualify Show work And please show steps

n=5
p=0.7
a)
(0.7)^5 = 0.16807

b)
(0.7)^4 * (0.3) * C(5 ,4) + (0.7)^5 = 0.36015 + 0.16807 = 0.52822

c)
(0.7)^3 * (0.3)^2 * C(5,3) + (0.7)^4 * (0.3) * C(5, 4) + (0.7)^5 = 0.3087 + 0.36015 + 0.16807 = 0.83692


EDIT:Before you're confused
C(5,3) =P(3)
C(5,4) =P(4)

[Morbid]

n=5
p=0.7
a)
(0.7)^5 = 0.16807

b)
(0.7)^4 * (0.3) * C(5 ,4) + (0.7)^5 = 0.36015 + 0.16807 = 0.52822

c)
(0.7)^3 * (0.3)^2 * C(5,3) + (0.7)^4 * (0.3) * C(5, 4) + (0.7)^5 = 0.3087 + 0.36015 + 0.16807 = 0.83692


EDIT:Before you're confused
C(5,3) =P(3)
C(5,4) =P(4)

Awh, Niku beat me to it. So far that is correct. Props to Niku!

P.S. Sorry for trolling you Niku in that other post, just sleepy .

[Poison]

n=5
p=0.7
a)
(0.7)^5 = 0.16807

b)
(0.7)^4 * (0.3) * C(5 ,4) + (0.7)^5 = 0.36015 + 0.16807 = 0.52822

c)
(0.7)^3 * (0.3)^2 * C(5,3) + (0.7)^4 * (0.3) * C(5, 4) + (0.7)^5 = 0.3087 + 0.36015 + 0.16807 = 0.83692


EDIT:Before you're confused
C(5,3) =P(3)
C(5,4) =P(4)

hope its right ill pm you when i get the work back

[Niku ・(￣∀￣)・]

hope its right ill pm you when i get the work back

alright

[DarkLordXYZ]

Well done How long did you take to find em?
4 minutes here, no paper work.

n=5
p=0.7
a)
(0.7)^5 = 0.16807

b)
(0.7)^4 * (0.3) * C(5 ,4) + (0.7)^5 = 0.36015 + 0.16807 = 0.52822

c)
(0.7)^3 * (0.3)^2 * C(5,3) + (0.7)^4 * (0.3) * C(5, 4) + (0.7)^5 = 0.3087 + 0.36015 + 0.16807 = 0.83692


EDIT:Before you're confused
C(5,3) =P(3)
C(5,4) =P(4)

[Niku ・(￣∀￣)・]

Well done How long did you take to find em?
4 minutes here, no paper work.

about 7 minutes with paperwork . I can't even do without paper work ._.

[DarkLordXYZ]

you in college yet?

about 7 minutes with paperwork . I can't even do without paper work ._.

[Schuba]

I'm in stats class right now haha.

[Niku ・(￣∀￣)・]

you in college yet?

yes and last sem .
I sucks at math basically . lol