SolvedAdding 2 huge numbers using vectors

Type Name	Bytes	Other Names		Range of Values
int 		4 	signed 			–2,147,483,648 to 2,147,483,647

#include <iostream>
#include <vector>
#include <string>

using namespace std;

int asciiToInt(char ch)
{
	return (ch - '0');
}

int main()
{
	vector<int> largeInt1(12, 0); // initialize to zero
	vector<int> largeInt2(12, 0); // initialize to zero
	vector<int> finalInt(13, 0); // initialize to zero
	
	// Loop four times
	for (int i = 1; i <= 8; i++)
	{
		// Create a string variable for the input and the vectorIndex and finalIntIndex will be used for assigning each number in the proper position in the vectors
		string number;
		int vectorIndex = 11, finalIntIndex = 12;

		cin >> number;

		// Check that the number's length is not longer than the elements in the vector
		if (number.length() > largeInt1.size())
		{
			cout << "That number is too large. Please try again" << endl;
			i -= 1;
			continue;
		}

		// If i is even, meaning we're getting input from the second or fourth number
		if ((i % 2) == 0)
		{
			// Assign each character number to the element in the vector. Going from right to left for the vector and the number since you add right to left
			for (int index = number.length() - 1; index >= 0; index--)
			{
				largeInt2[vectorIndex] = asciiToInt(number[index]);
				vectorIndex -= 1;
			}

			// Since we're on the second or fourth number, start adding each vector together, starting from right to left
			for (int index = largeInt1.size() - 1; index >= 0; index--, finalIntIndex--)
			{
				// Add the elements in largeInt1 and largeInt2 together at the same index in the current index for finalInt
				finalInt[finalIntIndex] += largeInt1[index] + largeInt2[index];

				// Check to see if that finalInt[finalIntIndex] is > 9 and we're not on the 0 index. If the number is then you need to subtract 10, storing the difference in the element one left of finalInt
				if (finalInt[finalIntIndex] > 9 && index > 0)
				{
					
				}
			}

			// Print your answer, be sure to clear the vectors (set everything back to 0) so the next set of numbers are not being added on top of this set
			
		}
		// We're on the first or third input
		else
		{
			// Assign each character number to the element in the vector. Going from right to left for the vector and the number since you add right to left
			for (int index = number.length() - 1; index >= 0; index--)
			{
				largeInt1[vectorIndex] = asciiToInt(number[index]);
				vectorIndex -= 1;
			}
		}
	}
}

cin >> number;
// assign the elements in the number to the elements in the first vector
cin >> number;
// assign the elements in the number to the element in the second vector

#include <iostream>
#include <vector>
#include <cctype>
#include <stdexcept>
#include <algorithm>
#include <numeric>
#include <string>
#include <functional>
#include <assert.h>
#include <sstream>
using namespace std;

int addition(string input1, string input2, int &result, vector<int> &largeInt1, vector<int> &largeInt2, vector<int> &finalInt);


int main() {
	vector<int> largeInt1 (12, 0); // initialize to zero
	vector<int> largeInt2 (12, 0); // initialize to zero
	vector<int> finalInt (13, 0); // initialize to zeros

	int result, flength;

	string input1, input2, results;

	cin >> input1;
	cin >> input2;
	for(int i = 0; i < input1.size(); i++) {
		cout << input1.at(i);
	}

	for(int i = 0; i < input2.size(); i++) {
		cout << input2.at(i);
	}
	largeInt1.resize(input1.size());
	largeInt2.resize(input2.size());

	flength = largeInt1.size()+largeInt2.size();

	finalInt.resize(flength);
	result = addition(input1, input2, result, largeInt1, largeInt2, finalInt);

	stringstream convert;
	convert << result;
	results = convert.str();

	cout << "String Conversion is: " << results << endl;
	for (unsigned i=0; i<input1.length(); ++i)
		{
			finalInt[i] = input1.at(i);
		}

	for(int i = finalInt.size(); i <= 0; i--) {
		cout << finalInt[i];
	}


	return 0;
}

int addition(string input1, string input2, int &result, vector<int> &largeInt1, vector<int> &largeInt2, vector<int> &finalInt){

	int length, base, last, remainder;
	bool isOdd;

	for (int i=0; i<input1.length(); ++i)
	{
		largeInt1[i] = input1.at(i);
	}

	for (int i = 0; i<input2.length(); i++) {
		largeInt2[i] = input2.at(i);
	}

	cout << "Input to LargeInt1: ";
	for(int i = 0; i < largeInt1.size(); i++) {
		cout << largeInt1[i] << " ";
		cout << endl;
	}
	cout << endl;
	cout << "Input to LargeInt2: ";
	for(int i = 0; i < largeInt2.size(); i++) {
		cout << largeInt2[i];
		cout << endl;
	}
	cout << endl;
	length = input1.size()+input2.size();
	if((length & 1) == 0) {
	} else {
		isOdd = true;
	}

	last = largeInt1.size();
	for(int i = 0; i <= length; i++) {
		base = largeInt1[i]+largeInt2[i];
		cout << "Base in << " << i << ": " << base << endl;
		if(base >= 10) {
			remainder = base-9;
			finalInt[i] = base-remainder;
			cout << "Remainder in << " << i << ": " << remainder << endl;
		} else {
			finalInt[i] = base;
		}
	}
cout << "Result is: " << result << endl;
return result;
}