[question] switch/class/struct
[question] switch/class/struct
I'll just give a big beefy example :
(my issue is that this code is wrong. I need to figure out how to properly call a function, if that function contains variables from a struct, class, enum or basically anything.) <--- Not sure if this makes sense .
actually just so it's easier for me to understand cuz my brain isnt workin so great right now, i basically need to know how to call ChoosePosition(sex positions); in my main function in this situation.
Code:
#include "stdafx.h"
#include <iostream>
using namespace std;
void ChoosePosition(sex positions);
enum sex
{
doggystyle,
butterfly,
anal,
missionary,
};
int _tmain(int argc, _TCHAR* argv[],sex positions)
{
ChoosePosition(sex positions);
return 0;
}
void ChoosePosition(sex position){
switch(position){
case(doggystyle):
cout<<"ROUGHH!"<<endl;
case(anal):
cout<<"kinky."<<endl;
break;
case(missionary):
cout<<"normal i guess."<<endl;
break;
case(butterfly):
cout<<"I dont even know what this is..."<<endl;
break;
default:
cout<<"whatever you want it to be baby"<<endl;
break;
}
}
actually just so it's easier for me to understand cuz my brain isnt workin so great right now, i basically need to know how to call ChoosePosition(sex positions); in my main function in this situation.
i havent seen enums much lately. I guess use alternatives /
i think the problem is that you declared the enum after your function prototype.
i think the problem is that you declared the enum after your function prototype.
Originally Posted by Koreans
i havent seen enums much lately. I guess use alternatives /
i think the problem is that you declared the enum after your function prototype.
i think the problem is that you declared the enum after your function prototype.
I'm baffled
The same thing seems to happen for structs and classes though. If i make a struct outside of a function, make a function that uses the variables, and then try to call it in the main function it doesnt work. The error is always that the type in the function call is invalid.. so i try different types and i took the type out altogether and it just says that its undefined XD. Even when I took everything out of the brackets it says that there's too few arguements.
STUMPED.
[Highlight=C++]
struct Person
{
char* name;
int age;
}
void SomeFunction(Person instance)
{
cout << instance.name;
return;
}
int main()
{
Person Void;
Void.name = "Idk";
Void.age = 14;
SomeFunction(Void);
}
[/Highlight]
NOTE: void is a data type but in this case I was using my username as a variable name, don't think of it as the void data type.
struct Person
{
char* name;
int age;
}
void SomeFunction(Person instance)
{
cout << instance.name;
return;
}
int main()
{
Person Void;
Void.name = "Idk";
Void.age = 14;
SomeFunction(Void);
}
[/Highlight]
Code:
Output: "Idk"
Move the enum above the function prototype..
This is what I used, worked for me:
This is what I used, worked for me:
Code:
#include <iostream>
using namespace std;
enum sex
{
doggystyle,
butterfly,
anal,
missionary,
};
void ChoosePosition(sex positions);
int main()
{
ChoosePosition(sex(doggystyle));
return 0;
}
void ChoosePosition(sex position){
switch(position){
case(doggystyle):
cout<<"ROUGHH!"<<endl;
case(anal):
cout<<"kinky."<<endl;
break;
case(missionary):
cout<<"normal i guess."<<endl;
break;
case(butterfly):
cout<<"I dont even know what this is..."<<endl;
break;
default:
cout<<"whatever you want it to be baby"<<endl;
break;
}
}
Figured it out thanks guys 
!
!Small correction ...
Originally Posted by Void
Originally Posted by Void
[Highlight=C++]
int main()
{
Person Void;
Void.name = "PedoWaldo";
Void.age = 23;
SomeFunction(Void);
}
[/Highlight]
int main()
{
Person Void;
Void.name = "PedoWaldo";
Void.age = 23;
SomeFunction(Void);
}
[/Highlight]
Originally Posted by why06
Small correction ...
Unable to +rep why 