X - MPGH

3^x+3^(x+1)=3^2+3^2

How would I calculate x?

Quadratic Equations

Originally Posted by Nathan

3^x+3^(x+1)=3^2+3^2

How would I calculate x?

Dont you mean x^3 ?
BTW if you fix that quadratic equasion ill finish it up quick :|
Because i have no idea if which one is powered to which :|

Solve the right, substitute for X so that left = right.

You need to clarify your equation more before we can understand what it's asking.

Not the right Section.

The answer is always cake

Originally Posted by DoubleDutch

The answer is always cake

I thought it was pie :[

3^x+3^(x+1)= 3²+3² =>
3^x+x+1 = 3²⁺² =>
3^2x+1 = 3⁴

I don't know how to go further...

Originally Posted by Black Eyed Peas

3^x+3^(x+1)= 3²+3² =>
3^x+x+1 = 3²⁺² =>
3^2x+1 = 3⁴

I don't know how to go further...

Take the natural log of both sides then solve for x.

Originally Posted by iverson954360

Take the natural log of both sides then solve for x.

You mean like this?

2x+1=4 => 2x=4-1 => 2x=3 => x=1.5

Then I would go back to the equasion and put the "x" into it:

3^{2(1.5) + 1} = 3⁴
3³⁺¹ = 3⁴
3⁴ = 3⁴

God I never understood maths ._.

Originally Posted by Black Eyed Peas

3^x+3^(x+1)= 3²+3² =>
3^x+x+1 = 3²⁺² =>
3^2x+1 = 3⁴

I don't know how to go further...

3² + 3² = 9 + 9 = 18
3²⁺² = 81

But the question is: 3^x+3^x+1=3²+3². What is x?
I can't seem to figure it out.

@iverson954360, halp please

Better explained solution: http://www.wolframalph*****m/input/?i=3^x%2B3^%28x%2B1%29%3D3^2%2B3^2

Enjoy

O man i suck hard at this!

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