Pointers/addresses

Originally Posted by Auxilium

Remember it'd give it to Array[1].
Get into the habit it starts from 0. even though you declare [php]int array[3][/php]
it really only goes from [php]array[0] to array[2][/php]
if you dont do this, youll get ugly runtime errors

NO.

I UNDERSTAND THAT.

I am purposely accessing the last array.

Originally Posted by VvITylerIvV

NO.

I UNDERSTAND THAT.

I am purposely accessing the last array.

What for? You'd get bounds errors. My brother got a bsod from a bounds errors once

Originally Posted by Auxilium

What for? You'd get bounds errors. My brother got a bsod from a bounds errors once

I wouldn't get any errors. I am accessing the last array because it's the array I wanted to access. If I were to access array[3] there would be errors, but because there are three arrays, array[2] is perfectly valid.

Originally Posted by Toxic Waltz

just test it

How am I supposed to test that, no matter what happens I get the same result. array[2] = 2222; is either assigning 2222 to array[2] or assigning 2222 to the value pointed by array[2] (which is array[2])

Which means that either way, array[2] ends up getting the value 2222. It's a question that is meaningless but I need to know whether or not it is assigned or the value pointed by array[2] is assigned.

Originally Posted by VvITylerIvV

what happens I get the same result. array[2] = 2222; is either assigning 2222 to array[2] or assigning 2222 to the value pointed by array[2] (which is array[2])

Which means that either way, array[2] ends up getting the value 2222. It's a question that is meaningless but I need to know whether or not it is assigned or the value pointed by array[2] is assigned.

isn't that exactly the same?

you just change the value where array[2] is pointing to to 2222

It's easier to declare it like
[php]int array[3] {number, number, number};[/php]

if you want them to be null, just declare 0, because null is 0 anywayz

Originally Posted by Auxilium

It's easier to declare it like
[php]int array[3] {number, number, number};[/php]

I know that... but I needed to assign just a single array, to ask my question. I understand arrays. I understand how to assign variables to them. I understand everything about them. EXCEPT.

When I use array[2] = 2222;

does it assign 2222 to array[2] or does it assign 2222 to the value pointed by array[2]

PLEASE DO NOT REPLY UNLESS YOU ARE GOING TO ANSWER MY DAMN QUESTION.

Originally Posted by VvITylerIvV

I know that... but I needed to assign just a single array, to ask my question. I understand arrays. I understand how to assign variables to them. I understand everything about them. EXCEPT.

When I use array[2] = 2222;

does it assign 2222 to array[2] or does it assign 2222 to the value pointed by array[2]

PLEASE DO NOT REPLY UNLESS YOU ARE GOING TO ANSWER MY DAMN QUESTION.

They're the same. Like Toxic said.

And array[2] isnt pointed to. It points to array[0]

im going to bed goodnight

Originally Posted by Auxilium

They're the same. Like Toxic said.

And array[2] isnt pointed to. It points to array[0]

im going to bed goodnight

int array[5] = {16, 15, 14, 13, 12 };

assigns the values to an address

as seen here

1232 ------- 1233 ---------- 1234 --------- 1235 --------- 1236 (addresses)
16 ---------- 15 ------------- 14 ------------ 13 ------------- 12 (values)

array[4] would point to the value of 1236, which is array[4]

I'm done here, because nobody understands my question...

I am going to ask both my questions which I need answered here. do NOT reply unless you are going to answer one, if not both. If you have to say anything else do NOT reply.
1. Does array[4] hold a value, or does it point to an address?
2. Does array[4] = 4444 change the value of the address pointed by array[4](1236) or does it directly change the value of array[4]? (they are pretty much the same thing but I need to know which one it does.)

again.
DO NOT REPLY UNLESS YOU ARE GOING TO ANSWER MY DAMN QUESTION.

Originally Posted by VvITylerIvV

int array[5] = {16, 15, 14, 13, 12 };

assigns the values to an address

as seen here

1232 ------- 1233 ---------- 1234 --------- 1235 --------- 1236 (addresses)
16 ---------- 15 ------------- 14 ------------ 13 ------------- 12 (values)

array[4] would point to the value of 1236, which is array[4]

I'm done here, because nobody understands my question...

I am going to ask both my questions which I need answered here. do NOT reply unless you are going to answer one, if not both. If you have to say anything else do NOT reply.
1. Does array[4] hold a value, or does it point to an address?
2. Does array[4] = 4444 change the value of the address pointed by array[4](1236) or does it directly change the value of array[4]? (they are pretty much the same thing but I need to know which one it does.)

again.
DO NOT REPLY UNLESS YOU ARE GOING TO ANSWER MY DAMN QUESTION.

What do you not understand about array[4] points to array[0]
So, it points, doesnt store a value.

and yes, changing the values of pointers changes the pointed object. Like i said in the other thread. Indirect access.

That SHOULD answer your question

An array is just memory stored away to hold values

Btw im going to say something about the pointer initialization. Either initialize it with NULL (already said, not sure), or just use malloc to allocate the memory for it.

Btw why are you learning Array now? i remember i learned about arrays before strings and etc... (C)

Originally Posted by 'Bruno

Btw im going to say something about the pointer initialization. Either initialize it with NULL (already said, not sure), or just use malloc to allocate the memory for it.

Btw why are you learning Array now? i remember i learned about arrays before strings and etc... (C)

I stated that on my other account