Originally Posted by Stephen
9.99999999999?
Originally Posted by Stephen
MPGH's Math Knowledge
Originally Posted by Stephen
Originally Posted by [QQ]?lol
@Alen Umm, flametastic today, aren't we?
I'll try not to repeat that in the next threads.
I'll try not to repeat that in the next threads.
I'm being 100% objective.
Originally Posted by Alen
Basic geometry is nowhere near comparable to relativity
I'm being 100% objective.
I'm being 100% objective.
Area of one triange x itself x itself ? 
.
.(1/3)b²h
That is off the top of my head from my geometry class that I had over 4 years ago. That I literally slept through. cbf to actually do the math though.
That is off the top of my head from my geometry class that I had over 4 years ago. That I literally slept through. cbf to actually do the math though.
Originally Posted by Heartview
(1/3)b²h
That is off the top of my head from my geometry class that I had over 4 years ago. That I literally slept through. cbf to actually do the math though.
That is off the top of my head from my geometry class that I had over 4 years ago. That I literally slept through. cbf to actually do the math though.
Originally Posted by Alen
So this is what got inspired by relativity. Goodie.
Originally Posted by Alen
So this is what got inspired by relativity. Goodie.
Frankly I like discussing physics more than just math anyways.
So the answer is 225.7707785, so lets say 225.77..
Am i right?
Am i right?
Originally Posted by Chuck Norris
So the answer is 225.7707785, so lets say 225.77..
Am i right?
Am i right?
Base of a regular four-sided pyramid is a square with sides of length a=8m with a diagonal long 8√2m. (diagonal is the length of the side * √2)
Consider the triangle that makes up half the diagonal length: d/2 = 8√2 = 4√2m, the lateral edge of the length b=12m and the height "h".
The Pythagorean theorem states:
b^2 = h^2 + (d/2)^2
We get that:
12^2 = h^2 + (4√2)^2, it follows that h =√112 = 4√7m
Now we can calculate the volume:
V = 1/3 * B * h = 1/3 * a * h^2 = 1/3 * 8^2 * 4√7m^3 = 256/3√7m^3 = 225.77m^3
Originally Posted by [QQ]?lol
YES! THE ANSWER IS CORRECT!!!! HERE IS THE EXPLANATION:
Base of a regular four-sided pyramid is a square with sides of length a=8m with a diagonal long 8√2m. (diagonal is the length of the side * √2)
Consider the triangle that makes up half the diagonal length: d/2 = 8√2 = 4√2m, the lateral edge of the length b=12m and the height "h".
The Pythagorean theorem states:
b^2 = h^2 + (d/2)^2
We get that:
12^2 = h^2 + (4√2)^2, it follows that h =√112 = 4√7m
Now we can calculate the volume:
V = 1/3 * B * h = 1/3 * a * h^2 = 1/3 * 8^2 * 4√7m^3 = 256/3√7m^3 = 225.77m^3
What the fuck ?
Originally Posted by Chuck Norris
at first i did 0.33 * 8 * 8 * 10.58, which sounded to be the same as 1/3..
When i did 8 * 8 * 10.58 / 3.. the correct answer showed up..
Weird..
When i did 8 * 8 * 10.58 / 3.. the correct answer showed up..
Weird..
Congratz!
Originally Posted by Shadeyz346
What the fuck ?
Originally Posted by [QQ]?lol
Yeah, small mistakes always fuck up everything.
Congratz!
It's called math. Learn it!
Originally Posted by Shadeyz346
I'm 12 , kiddo .
at first i did 0.33 * 8 * 8 * 10.58, which sounded to be the same as 1/3..
When i did 8 * 8 * 10.58 / 3.. the correct answer showed up..
Weird..
When i did 8 * 8 * 10.58 / 3.. the correct answer showed up..
Weird..