Large Char Array!

I need help creating a long char array. Or is there a much simpler way to do this? I dont want to type it out to 30000. Is there a much shorter way to do this?

char *num[] = { "1", "2", .., "29000", "30000" };

Dude come on this is easy... I'll give you something to work with...

Code:

int yourgayarray[];
for( int i =0; i < 3000; i++ ) 
{
yourgayarray[i] = i;
}

use ints its better and easier

Use a For loop and Sprintf function

Originally Posted by matypatty

Dude come on this is easy... I'll give you something to work with...

Code:

int yourgayarray[];
for( int i =0; i < 3000; i++ ) 
{
yourgayarray[i] = i;
}

use ints its better and easier

He asked for a Char Array, Not an array of integers.......

same principle apply's

for i:= 0 to 3000 do
CharArray[i]:= IntToStr(i); <--- convert Integer to a String..

Originally Posted by Departure

He asked for a Char Array, Not an array of integers.......

same principle apply's

for i:= 0 to 3000 do
CharArray[i]:= IntToStr(i); <--- convert Integer to a String..

Sprintf should do the job.

Originally Posted by Departure

He asked for a Char Array, Not an array of integers.......

same principle apply's

for i:= 0 to 3000 do
CharArray[i]:= IntToStr(i); <--- convert Integer to a String..

where would i place this. i can't put it as global though.

i am doing this

Code:

	for(int i = 0;  i < 30000; i++)
	{
		largeArray[i] = (char *)i;
	}

but my menu crashes when i want to turn on the hack to like 500

another method i tried but crashes

Code:

	char buffer [ FILENAME_MAX ];
    for(int i = 0;  i < 30000; i++)
	{
		sprintf(buffer, "%d", i);
		largeArray[i] = buffer;
	}

	return 0;

Originally Posted by Braco22

where would i place this. i can't put it as global though.

i am doing this

Code:

	for(int i = 0;  i < 30000; i++)
	{
		largeArray[i] = (char *)i;
	}

but my menu crashes when i want to turn on the hack to like 500

another method i tried but crashes

Code:

	char buffer [ FILENAME_MAX ];
    for(int i = 0;  i < 30000; i++)
	{
		sprintf(buffer, "%d", i);
		largeArray[i] = buffer;
	}

	return 0;

In this loop, i is an of an int data type. You are referencing it in your sprintf method call as a double (%d)

Code:

 for(int i = 0;  i < 30000; i++)
	{
		sprintf(buffer, "%i", i);
		largeArray[i] = buffer;
	}

Code:

char* None[30000];
for (int Of = 0; Of < 30000; ++Of)
{
	char* YouKnowCPP = new char[15];
	_itoa(Of, YouKnowCPP, 10);
	None[Of] = YouKnowCPP;
}

Originally Posted by Braco22

Code:

int len = 30000;
char* num[] = new char*[len];
for (int i = 0; i < len; i++)
  num[i] = iota(i);

Present!

Originally Posted by matypatty

Dude come on this is easy... I'll give you something to work with...

Code:

int yourgayarray[];
for( int i =0; i < 3000; i++ ) 
{
yourgayarray[i] = i;
}

use ints its better and easier

Unfortunately, you can't just assume that without knowing what the purpose of the array is.

Why do a char when it's easier to do an int but w/e

Originally Posted by Braco22

where would i place this. i can't put it as global though.

i am doing this

Code:

	for(int i = 0;  i < 30000; i++)
	{
		largeArray[i] = (char *)i;
	}

but my menu crashes when i want to turn on the hack to like 500

another method i tried but crashes

Code:

	char buffer [ FILENAME_MAX ];
    for(int i = 0;  i < 30000; i++)
	{
		sprintf(buffer, "%d", i);
		largeArray[i] = buffer;
	}

	return 0;

LOL

Code:

	char* largeArray[30000];
        for(int i = 0;  i < 30000; i++)
	{
                char buffer [ 0x10 ];
		sprintf_s(buffer, "%d", i);
		largeArray[i] = buffer;
	}

	return 0;

Large Char Array!

Post a Reply

Similar Threads

Tags for this Thread