Question28_4

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28_4
i used this code for close 28_3
Code:
DWORD bypass = CShell;
bypass = FindPattern(CShell, 0xFFFFFF, (PBYTE)"\xE8\x00\x00\x00\x00\x8B\xF0\x83\xC4\x04\x85\xF6\x0F\x84\x00\x00\x00\x00\xD9\x86\x00\x00\x00 \x00",(char*)"x????xxxxxxxxx????xx????");
bypass = bypass - CShell;

int NewAddress = bypass - 0x8;
*(byte*)(CShell + NewAddress + 0) = 0xE9;
*(int*)(CShell + NewAddress + 1) = 0x1F8;
*(byte*)(CShell + NewAddress + 5) = 0x90;
but in TD i take 28_4

somebody tell me how to remove this fck error

thanks
XD don't jump over he bypass... It gave a sexy error, you need a workaround...
look at old 28_3 error remover and you will understand the logic, that isen't jumping, but calling your function and replace it whit original bypass, get it ?
Quote Originally Posted by XarutoUsoCrack View Post
look at old 28_3 error remover and you will understand the logic, that isen't jumping, but calling your function and replace it whit original bypass, get it ?
Which got patched :/
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