Math problem
Can anyone please explain to me how to solve sin(x)= -1 where the possible solutions for the angle is between 0 and 4pi ? i.e not in between 0 and 360 degrees?
Math problem
x = arc sin (-1 )
Originally Posted by SuchAPirate
x = arc sin (-1 )
That is the only way to solve it @SirusFPS
Originally Posted by SuchAPirate
That is the only way to solve it @SirusFPS
so X1 = 3pi/2 and X2 = 7pi/2
Originally Posted by SirusFPS
Can anyone please explain to me how to solve sin(x)= -1 where the possible solutions for the angle is between 0 and 4pi ? i.e not in between 0 and 360 degrees?
so in the range of 0 to 4pi, your only answers here are (3/2)*pi and (7/2)*pi.
Originally Posted by Hero
sin(x) = -1 if x = 2pi*n + (3/2)*pi, where n = 0, 1, 2, 3, ....
so in the range of 0 to 4pi, your only answers here are (3/2)*pi and (7/2)*pi.
so in the range of 0 to 4pi, your only answers here are (3/2)*pi and (7/2)*pi.
Originally Posted by SirusFPS
thank you, that makes sense to me!
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