C++ Array [Solved]

Hello I have this code

Code:

srand ( time(NULL) );
	int bad1 = rand() % 9 + 1;
	int bad2 = rand() % 9 + 1;
	int bad3 = rand() % 9 + 1;
	int position = rand() % 9 + 1;
	int table1[] = {0, 0, 0, 0, 0, 0, 0, 0, 0};
	int table2[] = {0, 0, 0, 0, 0, 0, 0, 0, 0};
	int table3[] = {0, 0, 0, 0, 0, 0, 0, 0, 0};
	int table4[] = {0, 0, 0, 0, 0, 0, 0, 0, 0};
	table1[position] = position;
	table2[bad1] = bad1;
	table3[bad2] = bad2;
	table4[bad3] = bad3;

But I prefer to use chars for example

Code:

table1[position] = "D";

But that gives me an error.. any help to use char on a int array?

"D" isn't a char. 'D' is. Double quotes mean a char array (string), regardless of whether there is only 1 char in the array.

So should be

Code:

table2[bad1] = 'D';

or ? didnt understand some wordscause im not english.. can you explain?

Originally Posted by alvaritos

So should be

Code:

table2[bad1] = 'D';

or ? didnt understand some wordscause im not english.. can you explain?

Yes. That's right.

Code:

	srand ( time(NULL) );
	char *num;
	int bad1 = rand() % 10;
	int bad2 = rand() % 9 + 1;
	int bad3 = rand() % 9 + 1;
	int position = rand() % 9 + 1;
	int table1[] = {0, 0, 0, 0, 0, 0, 0, 0, 0};
	int table2[] = {0, 0, 0, 0, 0, 0, 0, 0, 0};
	int table3[] = {0, 0, 0, 0, 0, 0, 0, 0, 0};
	int table4[] = {0, 0, 0, 0, 0, 0, 0, 0, 0};
	table1[position] = position;
	table2[bad1] = 'D';
	table3[bad2] = bad2;
	table4[bad3] = bad3;

Using that code just gives me all numbers and the letter 'D' becomes a big number ex : 68 ...

Originally Posted by alvaritos

Code:

	srand ( time(NULL) );
	char *num;
	int bad1 = rand() % 10;
	int bad2 = rand() % 9 + 1;
	int bad3 = rand() % 9 + 1;
	int position = rand() % 9 + 1;
	int table1[] = {0, 0, 0, 0, 0, 0, 0, 0, 0};
	int table2[] = {0, 0, 0, 0, 0, 0, 0, 0, 0};
	int table3[] = {0, 0, 0, 0, 0, 0, 0, 0, 0};
	int table4[] = {0, 0, 0, 0, 0, 0, 0, 0, 0};
	table1[position] = position;
	table2[bad1] = 'D';
	table3[bad2] = bad2;
	table4[bad3] = bad3;

Using that code just gives me all numbers and the letter 'D' becomes a big number ex : 68 ...

Yea, because that's the ascii value of that char.

How I convert it to letter?

Originally Posted by alvaritos

How I convert it to letter?

Use the char data type instead of int.

e.g; [highlight=c++]char lalala = 'D';[/highlight]

Code:

srand ( time(NULL) );
	char num = 'D';
	int bad1 = rand() % 10;
	int bad2 = rand() % 9 + 1;
	int bad3 = rand() % 9 + 1;
	int position = rand() % 9 + 1;
	int table1[] = {0, 0, 0, 0, 0, 0, 0, 0, 0};
	int table2[] = {0, 0, 0, 0, 0, 0, 0, 0, 0};
	int table3[] = {0, 0, 0, 0, 0, 0, 0, 0, 0};
	int table4[] = {0, 0, 0, 0, 0, 0, 0, 0, 0};
	table1[position] = position;
	table2[bad1] = num;
	table3[bad2] = bad2;
	table4[bad3] = bad3;

Continue getting number.

Code:

srand ( time(NULL) );
	char num = 'D';
	int bad1 = rand() % 10;
	int bad2 = rand() % 9 + 1;
	int bad3 = rand() % 9 + 1;
	int position = rand() % 9 + 1;
	int table1[] = {0, 0, 0, 0, 0, 0, 0, 0, 0};
	int table2[] = {0, 0, 0, 0, 0, 0, 0, 0, 0};
	int table3[] = {0, 0, 0, 0, 0, 0, 0, 0, 0};
	int table4[] = {0, 0, 0, 0, 0, 0, 0, 0, 0};
	table1[position] = position;
	table2[bad1] = num;
	table3[bad2] = bad2;
	table4[bad3] = bad3;

Continue getting number.

because of

table2[bad1] = num;

table2 is an array of ints..

You should read the basics. .___.

Variables. Data Types. - C++ Documentation

And that code seems really messy...

Make your arrays char arrays then, or typecast the elements.

Ok, solved thanks

/Marked Solved.

C++ Array [Solved]

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