Getting Started With C++ [Solved]

Alright so im just starting C++ and im reading C++ without fear the second edition and i just really needed some basic help with understanding what do i have to do to print all the numbers from n1 to n2 where n1 and n2 are two numbers specified by the user. Im using the program dev-c++ as my compiler. Thanks

Well, you will first need to define n1 and n2 as an int variable sinice they will be integers:

int n1, n2;

Then you will use the cin function to get user input:

std::cin>>n1;
std::cin>>n2;

Then you will want to print it, so you use the cout function:

std:: cout<<"First number is: "<<n1<<"\nSecond number is: "<<n2;

Keep us posted on your progress.

Originally Posted by 258456

He wants to print all the numbers in the range of n1 and n2 (inclusive).

Code:

#include <iostream>
#include <conio.h>
using namespace std;
void main()
{
int n1,n2;
cout << "Enter 1st Number: ";
cin >> n1;
cout << "Enter 2nd Number: ";
cin >> n2;
for(int x = n1;x<=n2;x++) //Initialize x to the number stored in n1. Then loop while x is less than or equal to the number stored in n2. (x++ increments the value of x after each iteration.
{
cout << "Number is: " << x << endl;
}
_getch();
}

Originally Posted by Hassan

He wants to print all the numbers in the range of n1 and n2 (inclusive).

Code:

#include <iostream>
#include <conio.h>
using namespace std;
void main()
{
int n1,n2;
cout << "Enter 1st Number: ";
cin >> n1;
cout << "Enter 2nd Number: ";
cin >> n2;
for(int x = n1;x<=n2;x++) //Initialize x to the number stored in n1. Then loop while x is less than or equal to the number stored in n2. (x++ increments the value of x after each iteration.
{
cout << "Number is: " << x << endl;
}
_getch();
}

Oops, my bad, i misread his post.

Thanks for the help!

Np. Marked Solved.

I was interested in making a Kill/Death Ratio Hack for Modern Warfare 3 can anyone help me get started? I just started to read some C++ books and i really need some professional help.

Thank you

Getting Started With C++ [Solved]

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