C++ modifying variables from outside main()

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i was wondering how to modify the following to make the loop end without using "return".
in otherwords im asking how to use "meow()" to directly edit "main()"s int1

Code:

void meow(int int1)
{
	int1 += 10;
	cout << int1 << endl;
}


int main()
{
	int int1 = 5;
	while(int1 < 100)
	{
	meow(int1);
	}

   system("pause");
    return 0;
}

Originally Posted by utherson601

i was wondering how to modify the following to make the loop end without using "return".
in otherwords im asking how to use "meow()" to directly edit "main()"s int1

Code:

void meow(int int1)
{
	int1 += 10;
	cout << int1 << endl;
}


int main()
{
	int int1 = 5;
	while(int1 < 100)
	{
	meow(int1);
	}

   system("pause");
    return 0;
}

Use a reference.

Code:

void meow(int& int1)
{
	int1 += 10;
	cout << int1 << endl;
}


int main()
{
	int int1 = 5;
	while(int1 < 100)
	{
	meow(int1);
	}

   system("pause");
    return 0;
}

You can also use a pointer (less desired method in C++, but only method in C):

Code:

void meow(int* int1)
{
	*int1 += 10;
	cout << *int1 << endl;
}


int main()
{
	int int1 = 5;
	while(int1 < 100)
	{
	meow(&int1);
	}

   system("pause");
    return 0;
}

However, this deafeat the purpose of a function, which is to be more or less self-contained. Rarely should you use references in this sort of context.

thanks, i almost gave up on trying to do it..... i really need to remember this ....

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