Originally Posted by Predator
You sure bruh?
Originally Posted by Predator
You sure bruh?
Genius.
Originally Posted by Predator
You sure bruh?
Originally Posted by arunforce
Math.floor(877/10)+Math.floor(87/10)+Math.ceil(8/10) = 87+8+1 = 96
Originally Posted by Gill Bates
Lol nope,wrong.
Originally Posted by arunforce
It's 276 like he said unless it's a riddle. GTFO
Originally Posted by Predator
You sure bruh?
LOLOLOL NICE.SOMEONE FINALLY FIGURED IT OUT.
but yea,I thought it was wrong cuz it was supposed to be 101-877 lol.
9/10 for you
I beat the system yay 
I was technically the first one that got this... I posted the answer in the other thread but you edited your damn message... -_-
Originally Posted by Elocrypt.
I was technically the first one that got this... I posted the answer in the other thread but you edited your damn message... -_-
Originally Posted by Gill Bates
Das true. @Predator,your answer is invalid,Invis got it lolz.
Its all cool!
Originally Posted by Predator
Yeah I saw but I was like... WELL I POSTED FIRST
Its all cool!
276 .
its 2 .
Alright, since you boys are done playing let me show you the real way we do things around here.
Suppose we have a list here for all the times the 7 Appears in the last decimal place (7, X7, XX7, example : 147) Lets call the list U.
U = {7, 17, 27, 37,..., 877}
The equation for any n is Un = 7 + 10n. so:
877 = 7 + 10n
870 = 10n
n = 87 so the number 7 appears 87 times in the last decimal place.
1 - Thus, Utotal = 87
___________________________________
Now , suppose we have another list for all the times the number 7 Appears in the second decimal place (7X, X7X, example : 70, 570) lets call this list U'
U' = {70, 170, 270, 370, ... , 870}
The equation for any n for this list would be : U'n = 70 + 100n
so:
870 = 70 + 100n
800 = 100n
n = 8 so the number 7 appears 9 times in the second decimal place.
2 - Thus, U'total = 9 ( the reason it is 9 is because we didn't add the first number (n = 0) )
___________________________________
Now we need another list to find out how many times the 7 appears in the second decimal place (7X, X7Y, example : 76)
Lets call this list Z.
Zn = {70, 71, 72,..., 79} =======> it appears 10 times for every 100 in the U' list
3 - So..., Ztotal = 9 * U'total = 90
___________________________________
Now lets see how many times the number 7 Appears in the first decimal place.. well this is easy, 7XX
the only number that has 7 in the first place in the range 1 - 877 is 700 so. it appears 1 time only.
But how many times does the number 7 appear from 700 to 799 ?? well thats also easy, it appears 100 times !
SO, the total times the number 7 appears is :
Utotal + Ztotal + 100*1 = 87 + 90 + 99 = 276
The number 7 appears 276 times from 1 to 877.
Okay now @Gill Bates , you better have me rewarded because i wasted valuable time figuring this out... so you better 10/10 me. bich.
Suppose we have a list here for all the times the 7 Appears in the last decimal place (7, X7, XX7, example : 147) Lets call the list U.
U = {7, 17, 27, 37,..., 877}
The equation for any n is Un = 7 + 10n. so:
877 = 7 + 10n
870 = 10n
n = 87 so the number 7 appears 87 times in the last decimal place.
1 - Thus, Utotal = 87
___________________________________
Now , suppose we have another list for all the times the number 7 Appears in the second decimal place (7X, X7X, example : 70, 570) lets call this list U'
U' = {70, 170, 270, 370, ... , 870}
The equation for any n for this list would be : U'n = 70 + 100n
so:
870 = 70 + 100n
800 = 100n
n = 8 so the number 7 appears 9 times in the second decimal place.
2 - Thus, U'total = 9 ( the reason it is 9 is because we didn't add the first number (n = 0) )
___________________________________
Now we need another list to find out how many times the 7 appears in the second decimal place (7X, X7Y, example : 76)
Lets call this list Z.
Zn = {70, 71, 72,..., 79} =======> it appears 10 times for every 100 in the U' list
3 - So..., Ztotal = 9 * U'total = 90
___________________________________
Now lets see how many times the number 7 Appears in the first decimal place.. well this is easy, 7XX
the only number that has 7 in the first place in the range 1 - 877 is 700 so. it appears 1 time only.
But how many times does the number 7 appear from 700 to 799 ?? well thats also easy, it appears 100 times !
SO, the total times the number 7 appears is :
Utotal + Ztotal + 100*1 = 87 + 90 + 99 = 276
The number 7 appears 276 times from 1 to 877.
Okay now @Gill Bates , you better have me rewarded because i wasted valuable time figuring this out... so you better 10/10 me. bich.
Originally Posted by somewhatpro
Alright, since you boys are done playing let me show you the real way we do things around here.
Suppose we have a list here for all the times the 7 Appears in the last decimal place (7, X7, XX7, example : 147) Lets call the list U.
U = {7, 17, 27, 37,..., 877}
The equation for any n is Un = 7 + 10n. so:
877 = 7 + 10n
870 = 10n
n = 87 so the number 7 appears 87 times in the last decimal place.
1 - Thus, Utotal = 87
___________________________________
Now , suppose we have another list for all the times the number 7 Appears in the second decimal place (7X, X7X, example : 70, 570) lets call this list U'
U' = {70, 170, 270, 370, ... , 870}
The equation for any n for this list would be : U'n = 70 + 100n
so:
870 = 70 + 100n
800 = 100n
n = 8 so the number 7 appears 9 times in the second decimal place.
2 - Thus, U'total = 9 ( the reason it is 9 is because we didn't add the first number (n = 0) )
___________________________________
Now we need another list to find out how many times the 7 appears in the second decimal place (7X, X7Y, example : 76)
Lets call this list Z.
Zn = {70, 71, 72,..., 79} =======> it appears 10 times for every 100 in the U' list
3 - So..., Ztotal = 9 * U'total = 90
___________________________________
Now lets see how many times the number 7 Appears in the first decimal place.. well this is easy, 7XX
the only number that has 7 in the first place in the range 1 - 877 is 700 so. it appears 1 time only.
But how many times does the number 7 appear from 700 to 799 ?? well thats also easy, it appears 100 times !
SO, the total times the number 7 appears is :
Utotal + Ztotal + 100*1 = 87 + 90 + 99 = 276
The number 7 appears 276 times from 1 to 877.
Okay now @Gill Bates , you better have me rewarded because i wasted valuable time figuring this out... so you better 10/10 me. bich.
Suppose we have a list here for all the times the 7 Appears in the last decimal place (7, X7, XX7, example : 147) Lets call the list U.
U = {7, 17, 27, 37,..., 877}
The equation for any n is Un = 7 + 10n. so:
877 = 7 + 10n
870 = 10n
n = 87 so the number 7 appears 87 times in the last decimal place.
1 - Thus, Utotal = 87
___________________________________
Now , suppose we have another list for all the times the number 7 Appears in the second decimal place (7X, X7X, example : 70, 570) lets call this list U'
U' = {70, 170, 270, 370, ... , 870}
The equation for any n for this list would be : U'n = 70 + 100n
so:
870 = 70 + 100n
800 = 100n
n = 8 so the number 7 appears 9 times in the second decimal place.
2 - Thus, U'total = 9 ( the reason it is 9 is because we didn't add the first number (n = 0) )
___________________________________
Now we need another list to find out how many times the 7 appears in the second decimal place (7X, X7Y, example : 76)
Lets call this list Z.
Zn = {70, 71, 72,..., 79} =======> it appears 10 times for every 100 in the U' list
3 - So..., Ztotal = 9 * U'total = 90
___________________________________
Now lets see how many times the number 7 Appears in the first decimal place.. well this is easy, 7XX
the only number that has 7 in the first place in the range 1 - 877 is 700 so. it appears 1 time only.
But how many times does the number 7 appear from 700 to 799 ?? well thats also easy, it appears 100 times !
SO, the total times the number 7 appears is :
Utotal + Ztotal + 100*1 = 87 + 90 + 99 = 276
The number 7 appears 276 times from 1 to 877.
Okay now @Gill Bates , you better have me rewarded because i wasted valuable time figuring this out... so you better 10/10 me. bich.
Originally Posted by Cartier
You get a cookie.
YESS! bitch, see that shit?.. @Predator i got a cookie son. /me
