The answer is... 7. 
Genius.
Originally Posted by somewhatpro
Alright, since you boys are done playing let me show you the real way we do things around here.
Suppose we have a list here for all the times the 7 Appears in the last decimal place (7, X7, XX7, example : 147) Lets call the list U.
U = {7, 17, 27, 37,..., 877}
The equation for any n is Un = 7 + 10n. so:
877 = 7 + 10n
870 = 10n
n = 87 so the number 7 appears 87 times in the last decimal place.
1 - Thus, Utotal = 87
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Now , suppose we have another list for all the times the number 7 Appears in the second decimal place (7X, X7X, example : 70, 570) lets call this list U'
U' = {70, 170, 270, 370, ... , 870}
The equation for any n for this list would be : U'n = 70 + 100n
so:
870 = 70 + 100n
800 = 100n
n = 8 so the number 7 appears 9 times in the second decimal place.
2 - Thus, U'total = 9 ( the reason it is 9 is because we didn't add the first number (n = 0) )
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Now we need another list to find out how many times the 7 appears in the second decimal place (7X, X7Y, example : 76)
Lets call this list Z.
Zn = {70, 71, 72,..., 79} =======> it appears 10 times for every 100 in the U' list
3 - So..., Ztotal = 9 * U'total = 90
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Now lets see how many times the number 7 Appears in the first decimal place.. well this is easy, 7XX
the only number that has 7 in the first place in the range 1 - 877 is 700 so. it appears 1 time only.
But how many times does the number 7 appear from 700 to 799 ?? well thats also easy, it appears 100 times !
SO, the total times the number 7 appears is :
Utotal + Ztotal + 100*1 = 87 + 90 + 99 = 276
The number 7 appears 276 times from 1 to 877.
Okay now @Gill Bates , you better have me rewarded because i wasted valuable time figuring this out... so you better 10/10 me. bich.
Suppose we have a list here for all the times the 7 Appears in the last decimal place (7, X7, XX7, example : 147) Lets call the list U.
U = {7, 17, 27, 37,..., 877}
The equation for any n is Un = 7 + 10n. so:
877 = 7 + 10n
870 = 10n
n = 87 so the number 7 appears 87 times in the last decimal place.
1 - Thus, Utotal = 87
___________________________________
Now , suppose we have another list for all the times the number 7 Appears in the second decimal place (7X, X7X, example : 70, 570) lets call this list U'
U' = {70, 170, 270, 370, ... , 870}
The equation for any n for this list would be : U'n = 70 + 100n
so:
870 = 70 + 100n
800 = 100n
n = 8 so the number 7 appears 9 times in the second decimal place.
2 - Thus, U'total = 9 ( the reason it is 9 is because we didn't add the first number (n = 0) )
___________________________________
Now we need another list to find out how many times the 7 appears in the second decimal place (7X, X7Y, example : 76)
Lets call this list Z.
Zn = {70, 71, 72,..., 79} =======> it appears 10 times for every 100 in the U' list
3 - So..., Ztotal = 9 * U'total = 90
___________________________________
Now lets see how many times the number 7 Appears in the first decimal place.. well this is easy, 7XX
the only number that has 7 in the first place in the range 1 - 877 is 700 so. it appears 1 time only.
But how many times does the number 7 appear from 700 to 799 ?? well thats also easy, it appears 100 times !
SO, the total times the number 7 appears is :
Utotal + Ztotal + 100*1 = 87 + 90 + 99 = 276
The number 7 appears 276 times from 1 to 877.
Okay now @Gill Bates , you better have me rewarded because i wasted valuable time figuring this out... so you better 10/10 me. bich.
Originally Posted by somewhatpro
YESS! bitch, see that shit?.. @Predator i got a cookie son. /me
Originally Posted by Predator
Im not your son bitch
Originally Posted by somewhatpro
i'm not your mom, SON!!!!...
You guys are still dumb as fuck.The answer is notepad + copy and paste
